MySQL选择查询中子选择的效率
我试图从数据库表的集合中产生一个报告,我发现我写的查询超慢。我意识到在选择查询中使用多个子查询会增加查询完成所需的时间,因为每行都需要对数据库进行多个子查询,但我能做些什么来使查询更快,更高效?MySQL选择查询中子选择的效率
我试过在准备好的语句中包装它,它没有什么作用,有没有一种方法可以让我更快地提取所需信息?
SELECT Contractor.id,
Contractor.Unique_ID,
Contractor.FName,
Contractor.SName,
Contractor.MIName,
Contractor.NI_Number,
Contractor.Address,
Contractor.Phone_Main,
Contractor.Phone_Mobile,
Contractor.Email,
Contractor.Bank_Name,
Contractor.Bank_Account_Name,
Contractor.Bank_Account_Sort_Code,
Contractor.Bank_Account_Number,
Contractor.DOB,
Contractors.DateTime_Account_Created,
Contractor.Payment_Frequency,
Contractor.Saving_Tax_Pref,
Contractor.Holiday_Savings_Pref,
Contractor.UTR,
Contractor.DateTime_Last_Logged_In,
Contractor.Leaving_Date,
Agency.Name,
(
SELECT ROUND(SUM(ContractorSavings.value - ContractorSavings.paidOutValue), 2)
FROM ContractorSavings
LEFT JOIN SavingsToPayJunction ON SavingsToPayJunction.SavingsId = ContractorSavings.id
WHERE fullyPaid = 0
AND ContractorSavings.type_id = 2
AND SavingsToPayJunction.ContractorId = Contractor.id
) AS 'Tax_Saving_Balance',
(
SELECT ROUND(SUM(ContractorSavings.value - ContractorSavings.paidOutValue), 2)
FROM ContractorSavings
LEFT JOIN SavingsToPayJunction ON SavingsToPayJunction.SavingsId = ContractorSavings.id
WHERE fullyPaid = 0
AND ContractorSavings.type_id = 2
AND SavingsToPayJunction.ContractorId = Contractor.id
) AS 'Holiday_Saving_Balance',
(
SELECT ROUND(SUM(Expense_Value),2)
FROM Contractor_Expenses
WHERE Contractor_ID = Contractor.id
AND authorised = 0
)AS 'Expenses_Claimed',
(
SELECT ROUND(SUM(Expense_Value - amountAllocated),2)
FROM Contractor_Expenses
WHERE Contractor_ID = Contractor.id
AND authorised = 1
AND fullyAllocated = 0
)AS 'Expenses_Authorised',
(
SELECT MAX(Contractor_Pay.Date_Earned)
FROM Contractor_Pay
WHERE Contractor_Pay.Contractor_ID = Contractor.Unique_ID
)AS 'Last_Pay_Date'
FROM Contractor
LEFT JOIN Agency ON Agency.id = Contractor.Agency_ID
笨拙的查询转储道歉。我期待着你的回应。
谢谢
*邮政的答案编辑*
对于那些关心时限等,答案降低我的查询时间缩短从超过3:00分钟到45秒。
你可以在每个那些在FROM子句(与GROUP BY Contractor_ID)子选择的就加入他们了:
SELECT
Contractor.id,
Contractor.Unique_ID,
Contractor.FName,
Contractor.SName,
Contractor.MIName,
Contractor.NI_Number,
Contractor.Address,
Contractor.Phone_Main,
Contractor.Phone_Mobile,
Contractor.Email,
Contractor.Bank_Name,
Contractor.Bank_Account_Name,
Contractor.Bank_Account_Sort_Code,
Contractor.Bank_Account_Number,
Contractor.DOB,
Contractors.DateTime_Account_Created,
Contractor.Payment_Frequency,
Contractor.Saving_Tax_Pref,
Contractor.Holiday_Savings_Pref,
Contractor.UTR,
Contractor.DateTime_Last_Logged_In,
Contractor.Leaving_Date,
Agency.Name,
Tax_Saving_Balance.val as Tax_Saving_Balance,
Holiday_Saving_Balance.val as Holiday_Saving_Balance,
Expenses_Claimed.val as Expenses_Claimed,
Expenses_Authorised.val as Expenses_Authorised,
Last_Pay_Date.val as Last_Pay_Date
FROM Contractor
LEFT JOIN Agency ON Agency.id = Contractor.Agency_ID
LEFT JOIN (
SELECT SavingsToPayJunction.ContractorId, ROUND(SUM(ContractorSavings.value - ContractorSavings.paidOutValue), 2) as val,
FROM ContractorSavings
LEFT JOIN SavingsToPayJunction ON SavingsToPayJunction.SavingsId = ContractorSavings.id
WHERE fullyPaid = 0
AND ContractorSavings.type_id = 2
GROUP BY SavingsToPayJunction.ContractorId
) as Tax_Saving_Balance ON Tax_Saving_Balance.ContractorId = Contractor.id
LEFT JOIN (
SELECT SavingsToPayJunction.ContractorId, ROUND(SUM(ContractorSavings.value - ContractorSavings.paidOutValue), 2) as val
FROM ContractorSavings
LEFT JOIN SavingsToPayJunction ON SavingsToPayJunction.SavingsId = ContractorSavings.id
WHERE fullyPaid = 0
AND ContractorSavings.type_id = 2
GROUP BY SavingsToPayJunction.ContractorId
) as Holiday_Saving_Balance ON Holiday_Saving_Balance.ContractorId = Contractor.id
LEFT JOIN (
SELECT Contractor_ID, ROUND(SUM(Expense_Value),2) as val
FROM Contractor_Expenses
WHERE authorised = 0
GROUP BY Contractor_ID
) as Expenses_Claimed ON Expenses_Claimed.Contractor_ID = Contractor.id
LEFT JOIN (
SELECT Contractor_ID, ROUND(SUM(Expense_Value - amountAllocated),2) as val
FROM Contractor_Expenses
WHERE authorised = 1
AND fullyAllocated = 0
GROUP BY Contractor_ID
) as Expenses_Authorised ON Expenses_Authorised.Contractor_ID = Contractor.id
LEFT JOIN (
SELECT Contractor_ID, MAX(Contractor_Pay.Date_Earned)
FROM Contractor_Pay
GROUP BY Contractor_ID
) as Last_Pay_Date ON Last_Pay_Date.Contractor_ID = Contractor.Unique_ID
我很感谢您的回应,您的回答中的方法实际上比我当前的查询更快。 出于兴趣,你知道它为什么更快吗? –
FROM子句中的子查询只运行一次(不相关) - 在您的查询中它们更简单,但每个承包商运行一次。在MySQL中,索引JOIN比相关子查询更快,子查询中的临时表为需要它们的字段获得自动索引(从5.6我认为)。 – Vatev
你使用corelated子查询。对于主查询中的每一行,您还将运行这些子查询。所以对于'n'行'承包商'表,你实际上正在运行。 '1+(n * 6)'查询。例如1000个承包商行,执行6001个查询。 –
是的,我知道。什么是更好的方法? –
许多这些子查询根本不必是子查询,例如'MAX(contractor_pay_umbrella)'。 –