从httppost响应中解析xml

问题描述：

执行http POST期间，我将响应存储为字符串响应。从httppost响应中解析xml

HttpResponse httpresponse = httpclient.execute(httppost); 
HttpEntity resEntity = httpresponse.getEntity(); 
response = EntityUtils.toString(resEntity);

如果我打印响应，它看起来像：

<?xml version="1.0" encoding="UTF-8"?> 
<response status="ok"> 
<sessionID>lo8mdn7bientr71b5kn1kote90</sessionID> 
</response>

我想刚才的SessionID存储为一个字符串。我试过

DocumentBuilderFactory factory = DocumentBuilderFactory.newInstance(); 
DocumentBuilder builder = factory.newDocumentBuilder(); 
InputSource is = new InputSource(new StringReader(xml));

各种方法这样，但它不会让我跑的代码，因为DocumentBuildFactory和InputSource的是无效的。

我应该怎样从XML中提取特定的字符串？

我的[KSOAP2（http://ksoap2.sourceforge.net/）是处理这种反应 – mihail 2012-08-15 14:55:18

答

这只是快速和肮脏的测试。它为我工作。

import java.io.IOException; 
import java.io.StringReader; 

import javax.xml.parsers.DocumentBuilder; 
import javax.xml.parsers.DocumentBuilderFactory; 
import javax.xml.parsers.ParserConfigurationException; 

import org.w3c.dom.Document; 
import org.w3c.dom.NodeList; 
import org.xml.sax.InputSource; 
import org.xml.sax.SAXException; 

public class Test { 
    public static void main(String[] args) { 
     String xml= "<?xml version=\"1.0\" encoding=\"UTF-8\"?><response status=\"ok\"><sessionID>lo8mdn7bientr71b5kn1kote90</sessionID></response>"; 
     DocumentBuilderFactory factory = DocumentBuilderFactory.newInstance(); 
     DocumentBuilder builder; 
     InputSource is; 
     try { 
      builder = factory.newDocumentBuilder(); 
      is = new InputSource(new StringReader(xml)); 
      Document doc = builder.parse(is); 
      NodeList list = doc.getElementsByTagName("sessionID"); 
      System.out.println(list.item(0).getTextContent()); 
     } catch (ParserConfigurationException e) { 
     } catch (SAXException e) { 
     } catch (IOException e) { 
     } 
    } 
}

输出： lo8mdn7bientr71b5kn1kote90

感谢的最好方式之一响应，这确实是唯一的问题，当我使用我的实际响应它没有。我认为这是因为该字符串包含不正确转义的引号。 – Ted 2012-08-15 17:30:12

我不确定你在响应中究竟得到了什么，有人猜测它可能在UTF字符串的开始处包含BOM（更多信息的Google XML BOM）。如果你有一个调试器（比如Eclipse中的调试器），应该非常直截了当地找出它和硬编码工作字符串之间的区别。 – 2012-08-15 18:54:16

如果响应的文本编码是UTF-8，也许它也值得尝试改变response = EntityUtils.toString（resEntity）; to response = EntityUtils.toString（resEntity，“UTF-8”）; – 2012-08-15 18:59:33

答

1.使用DOM Parser。

如：

DocumentBuilderFactory odbf = DocumentBuilderFactory.newInstance(); 
DocumentBuilder odb = odbf.newDocumentBuilder(); 
      InputSource is = new InputSource(new StringReader(xml)); 
      Document odoc = odb.parse(is); 
      odoc.getDocumentElement().normalize(); // normalize text representation 
      System.out.println ("Root element of the doc is " + odoc.getDocumentElement().getNodeName()); 
      NodeList LOP = odoc.getElementsByTagName("locations"); 
      int totalPersons =LOP.getLength(); 
      System.out.println("Total nos of locations:"+totalPersons); 

      for(int s=0; s<LOP.getLength() ; s++) 
      { 
       Node FPN =LOP.item(s); 
       if(FPN.getNodeType() == Node.ELEMENT_NODE) 
        { 

        Element latlon = (Element)FPN;                 

        NodeList oNameList1 = latlon.getElementsByTagName("featured");          
        Element firstNameElement = (Element)oNameList1.item(0); 
        NodeList textNList1 = firstNameElement.getChildNodes(); 
        //this.setLocationId(((Node)textNList1.item(0)).getNodeValue().trim());  
        featuredArr = changeToBoolean(((Node)textNList1.item(0)).getNodeValue().trim());         // value taken 
        System.out.println("#####The Parsed data#####"); 
        System.out.println("featured : " + ((Node)textNList1.item(0)).getNodeValue().trim());   
        System.out.println("#####The Parsed data#####"); 
    }

请参阅此链接了解详情：

http://tutorials.jenkov.com/java-xml/dom.html

从httppost响应中解析xml

相关推荐