在ObjC中工作，而不是迅速。什么是错误的，我正在用快速解析JSON解析
问题描述：
我只是想解析URL中的JSON， 下面的代码写在ObjC中运行良好，给我正确的响应， ，但代码写在swift 3.1中，没有给出正确的响应。 Giving me 500 Internal Error在ObjC中工作，而不是迅速。什么是错误的，我正在用快速解析JSON解析
我在做什么错。 任何人都可以指导。 在此先感谢。
我也尝试使用转换器从ObjC到Swift。 但它失败了一些错误，虽然我解决了这些错误，但仍然没有给出正确的输出。
下面是ObjC代码。
-(void)comparedatainserturl
{
NSError *error;
NSMutableArray *arr=[[NSMutableArray alloc]init];
NSMutableDictionary *dict=[[NSMutableDictionary alloc]init];
[dict setObject:@"e639e129d0f3ab7d" forKey:@"imei_no"];
[dict setObject:@"2017-08-29 12:18:44" forKey:@"current_time"];
[dict setObject:@"0" forKey:@"tbl_offer_details"];
[dict setObject:@"0" forKey:@"tbl_card_type"];
[dict setObject:@"0" forKey:@"tbl_dashboard"];
[dict setObject:@"0" forKey:@"tbl_category_details"];
[dict setObject:@"0" forKey:@"tbl_sub_category_details"];
[dict setObject:@"0" forKey:@"tbl_payment_option"];
[dict setObject:@"0" forKey:@"tbl_payment_option_provider"];
[dict setObject:@"0" forKey:@"tbl_like_favorite_share"];
[dict setObject:@"0" forKey:@"tbl_user_details"];
[arr addObject:dict];
NSLog(@"arra :- %@",[arr description]);
NSData *jsonData = [NSJSONSerialization dataWithJSONObject:arr options:NSJSONWritingPrettyPrinted error:&error];
NSString *jsonString = [[NSString alloc] initWithData:jsonData encoding:NSUTF8StringEncoding];
NSString *string = [NSString stringWithFormat:@"data=%@",jsonString];
NSLog(@"jsonData as string:\n%@", string);
NSData *data = [string dataUsingEncoding:NSUTF8StringEncoding];
NSString *urlString=[NSString stringWithFormat:@"%@",@"http://admin.scontos.com/index.php/Android_api/Offers_download"];
NSURL *url = [NSURL URLWithString:urlString];
NSMutableURLRequest *request = [NSMutableURLRequest requestWithURL:url];
[request setHTTPMethod: @"POST"];
[request setHTTPBody: data];
NSError *err;
NSURLResponse *response;
NSData *responseData = [NSURLConnection sendSynchronousRequest:request returningResponse:&response error:&err];
NSString *resSrt = [[NSString alloc]initWithData:responseData encoding:NSASCIIStringEncoding];
NSLog(@"gotresponsestring=%@", resSrt);
}
低于银行代码，
func comparedatainserturl() {
var arrayParams : NSDictionary = [:]
arrayParams = ["imei_no":"e639e129d0f3ab7d","current_time":"2017-08-2911:08:26","tbl_offer_details":"0","tbl_card_type":"0","tbl_dashboard":"0","tbl_category_details":"0","tbl_sub_category_details":"0","tbl_payment_option":"0","tbl_payment_option_provider":"0","tbl_like_favorite_share":"0","tbl_user_details":"0"]
print(arrayParams)
let valueArr : Array = [arrayParams]
print(valueArr)
let jsonData: Data? = try! JSONSerialization.data(withJSONObject: valueArr, options: .prettyPrinted)
let jsonString = String(data: jsonData!, encoding: String.Encoding.utf8)
let string: String = "data=\(jsonString)"
print("jsonData as string:\n\(string)")
let dataa: Data? = string.data(using: String.Encoding.utf8)
var _: NSError?
let url1:URL = URL(string:"http://admin.scontos.com/index.php/Android_api/Offers_download")!
let request:NSMutableURLRequest = NSMutableURLRequest(url: url1)
request.httpMethod = "POST"
request.httpBody = dataa
var response: URLResponse?
do{
let urlData: Data? = try NSURLConnection.sendSynchronousRequest(request as URLRequest, returning:&response)
let resstr = NSString(data: urlData!, encoding: String.Encoding.utf8.rawValue)
print("Response is \(resstr! as String)")
}catch{
print(error)
}
}
答
在您的swift代码中，您将追加以下字符串。
let jsonString = String(data: jsonData!, encoding: String.Encoding.utf8) /在以下代码行中，您将使用可选关键字和可选值附加JsonString并使用此“（）”。所以，你需要解开的可选值/
let string: String = "data=\(jsonString!)"
答
您的代码发送，有效地看起来像一个请求的身体：
data=[
{
"key1" : "value1",
"key2" : "value2", ...
}
]
这是不正确。
如果您的服务器期待只是JSON，你应该发送JSON而不
data=前缀。如果您的服务器期待
application/x-www-form-urlencoded请求，那么该值不能包含空格，换行符或其他任何保留字符。在这种情况下，您必须“百分比转义”请求的正文。
您应该确切地确认Web服务期望的内容，并相应地调整您的代码。
无关，我会退休NS类并留在Swift中。因此，假设你想只发送JSON，代码可能看起来像：
func comparedatainserturl() {
let arrayParams = [
[
"imei_no":"e639e129d0f3ab7d",
"current_time":"2017-08-2911:08:26",
"tbl_offer_details":"0",
"tbl_card_type":"0",
"tbl_dashboard":"0",
"tbl_category_details":"0",
"tbl_sub_category_details":"0",
"tbl_payment_option":"0",
"tbl_payment_option_provider":"0",
"tbl_like_favorite_share":"0",
"tbl_user_details":"0"
]
]
let data = try! JSONSerialization.data(withJSONObject: arrayParams)
let jsonString = String(data: data, encoding: .utf8)!
let string: String = "data=" + jsonString
print("jsonData as string:\n\(string)")
let url1 = URL(string:"http://admin.scontos.com/index.php/Android_api/Offers_download")!
var request = URLRequest(url: url1)
request.httpMethod = "POST"
request.httpBody = data
let task = URLSession.shared.dataTask(with: request) { data, response, error in
if let error = error {
print(error)
return
}
guard let data = data else { return }
let string = String(data: data, encoding: .utf8)
print("response is \(string)")
}
task.resume()
}
或者，如果服务器期待x-www-form-urlencoded要求：
let data = try! JSONSerialization.data(withJSONObject: arrayParams)
let jsonString = String(data: data, encoding: .utf8)!
let string: String = "data=" + jsonString.addingPercentEncodingForQuery()!
let url1 = URL(string:"http://admin.scontos.com/index.php/Android_api/Offers_download")!
var request = URLRequest(url: url1)
request.httpMethod = "POST"
request.httpBody = string.data(using: .utf8)
如果你使用这个程序，改编自％的逃生Alamofire的escape routine：
extension String {
public func addingPercentEncodingForQuery() -> String? {
let generalDelimitersToEncode = ":#[]@" // does not include "?" or "/" due to RFC 3986 - Section 3.4
let subDelimitersToEncode = "!$&'()*+,;="
var allowed = CharacterSet.urlQueryAllowed
allowed.remove(charactersIn: generalDelimitersToEncode + subDelimitersToEncode)
return addingPercentEncoding(withAllowedCharacters: allowed)
}
}
你尝试过什么基本的调试策略？ –
顺便说一句，我建议不要使用ObjC - > Swift转换器，如果可能的话。它们会生成直接翻译，这会导致代码非常糟糕。就像期待Google Translate将一首法语诗一样转换成英文。当然，所有的单词都会在那里，但它会是一首可怕的诗。 – Rob
你的网址是否有效？因为我收到了一些数据库错误。 –