MySQL查询命令两列,一个ASC另一个DESC
我正在尝试编写一个主题明智的优点列表。我用这mysql query
:MySQL查询命令两列,一个ASC另一个DESC
SELECT *
FROM results
ORDER BY qid ASC,
marks DESC
结果是:
但我需要的是这样的(看马克列,我需要得到相同qid
行,由marks
订购) :
请人帮我。
更新: 而这是result.sql
文件在您的电脑中创建表。
-- phpMyAdmin SQL Dump
-- version 3.5.2.2
-- http://www.phpmyadmin.net
--
-- Host: 127.0.0.1
-- Generation Time: Mar 09, 2013 at 05:40 PM
-- Server version: 5.5.27
-- PHP Version: 5.4.7
SET SQL_MODE="NO_AUTO_VALUE_ON_ZERO";
SET time_zone = "+00:00";
/*!40101 SET @[email protected]@CHARACTER_SET_CLIENT */;
/*!40101 SET @[email protected]@CHARACTER_SET_RESULTS */;
/*!40101 SET @[email protected]@COLLATION_CONNECTION */;
/*!40101 SET NAMES utf8 */;
--
-- Database: `ges_omeca`
--
-- --------------------------------------------------------
--
-- Table structure for table `results`
--
CREATE TABLE IF NOT EXISTS `results` (
`exam_id` int(11) NOT NULL AUTO_INCREMENT,
`sid` varchar(50) NOT NULL,
`qid` varchar(100) NOT NULL,
`corrects` int(3) NOT NULL,
`total_qs` int(3) NOT NULL,
`marks` float NOT NULL,
`date_time` datetime NOT NULL COMMENT 'DateTime when user submits the answer script.',
PRIMARY KEY (`exam_id`)
) ENGINE=InnoDB DEFAULT CHARSET=latin1 AUTO_INCREMENT=14 ;
--
-- Dumping data for table `results`
--
INSERT INTO `results` (`exam_id`, `sid`, `qid`, `corrects`, `total_qs`, `marks`, `date_time`) VALUES
(1, 'guest', 'EN_(Set-B)_(07.02.13)', 37, 40, 36.25, '2023-02-13 01:10:00'),
(2, 'guest', 'EN_(Set-B)_(07.02.13)', 11, 40, 10.25, '2013-02-23 01:56:58'),
(3, 'guest', 'P1_(Set-D)_(10.02.13)', 2, 100, 36.25, '2013-02-23 03:42:57'),
(4, 'guest', 'P1_(Set-B)_(09.02.13)', 5, 40, 5, '2013-02-23 03:46:59'),
(5, 'guest', 'EN_(Set-A)_(07.02.13)', 1, 40, 0.25, '2013-02-23 04:46:59'),
(6, 'guest', 'EN_(Set-A)_(07.02.13)', 6, 40, 5.5, '2013-02-23 04:59:59'),
(7, 'guest', 'P1_(Set-D)_(10.02.13)', 10, 100, 9.25, '2013-02-24 08:57:17'),
(8, 'guest', 'P1_(Set-B)_(09.02.13)', 5, 40, 5, '2013-02-24 01:23:50'),
(9, 'guest', 'EN_(Set-D)_(07.02.13)', 0, 40, -0.5, '2013-02-25 12:45:33'),
(10, 'guest', 'EN_(Set-D)_(07.02.13)', 2, 40, 1.5, '2013-02-25 01:45:38'),
(11, 'guest', 'P1_(Set-B)_(09.02.13)', 2, 40, 2, '2013-02-25 04:06:28'),
(12, 'guest', 'EN_(Set-C)_(07.02.13)', 5, 40, 4.5, '2013-02-25 04:42:27'),
(13, 'guest', 'P1_(Set-C)_(10.02.13)', 6, 40, 6, '2013-02-25 05:00:57');
/*!40101 SET [email protected]_CHARACTER_SET_CLIENT */;
/*!40101 SET [email protected]_CHARACTER_SET_RESULTS */;
/*!40101 SET [email protected]_COLLATION_CONNECTION */;
这是您需要的东西:
SELECT *
FROM results
ORDER BY SUBSTRING(qid
FROM 1
FOR 1) ASC , marks DESC
是的,它的工作,谢谢 – 2013-03-09 18:22:38
我真的不明白你的问题,但看这个结果,我已经注意到,记录由qid
包含EN
是第一个结果列表进行排序。
试试这个,
SELECT *
FROM tableName
ORDER BY CASE WHEN qid LIKE 'EN%' THEN 0
WHEN qid LIKE 'P1%' THEN 1
ELSE 2
END ASC,
marks DESC
有点错字:'P1%' – hjpotter92 2013-03-09 16:35:02
@DreamEater固定。谢谢.. – 2013-03-09 16:36:22
但表中可能包含很多东西,而不仅仅是EN和P1。这就是为什么我想要订购他们。 – 2013-03-09 16:38:04
这可以帮助你:
SELECT *
FROM results
ORDER BY SUBSTRING(qid FROM 1 FOR 9) ASC,
marks DESC
日期'2023-02-13'对我来说似乎合法。你如何产生期望的结果? – hjpotter92 2013-03-09 16:31:23
这是我编辑过的:D,请不要以为只有'qid'和'marks'就不要以为别的:) – 2013-03-09 16:35:11