尝试根据用户输入交换数组元素
问题描述:
因此,我必须交换数组中的两个元素,其中5个值,但交换的两个元素必须从键盘中取出。前面的问题是交换到特定的,我完成了,但我不知道如何从键盘上的数字被用于交换。其中一些是从前一个我知道我不得不交换的元素。尝试根据用户输入交换数组元素
import java.util.Scanner;
public class Swap2 {
public static void main(String []args) {
Scanner keyboardIn = new Scanner (System.in);
int[] numbers = new int []{12,9,33,28,5};
int temp = 0, first, second;
System.out.println ("Before the swap: ");
for(int i=0; i < numbers.length; i++) {
System.out.print(numbers[i] + " ");
}
System.out.println();
System.out.println ("Enter the first number to swap:");
first = keyboardIn.nextInt();
System.out.println ("Enter the second number to swap:");
second = keyboardIn.nextInt();
System.out.println();
temp = numbers[3];
numbers [3] = numbers [1];
numbers [1] = temp;
System.out.println ("After the swap:");
for (int i = 0; i < numbers.length; i++) {
System.out.print (numbers[i] + " ");
}
}
}
答
你必须定义指数开始......
import java.util.Scanner;
public class Swap {
public static void main(String[] args) {
Scanner keyboardIn = new Scanner(System.in);
/* enter code here */int[] numbers = new int[] { 12, 9, 33, 28, 5 };
int temp = 0, first, second;
int index1 = 0 , index2 = 0;
int j , k ;
System.out.println("Before the swap: ");
for (int i = 0; i < numbers.length; i++) {
System.out.print(numbers[i] + " ");
}
System.out.println();
System.out.println("Enter the first number to swap:");
first = keyboardIn.nextInt();
System.out.println("Enter the second number to swap:");
second = keyboardIn.nextInt();
System.out.println();
for(k = 0 ; k < numbers.length; k++){
if(numbers[k] == first)
index1 = k;
}
for(j = 0 ; j < numbers.length; j++){
if(numbers[j] == second)
index2 = j;
}
temp = numbers[index1];
numbers[index1] = numbers[index2];
numbers[index2] = temp;
System.out.println("After the swap:");
for (int i = 0; i < numbers.length; i++) {
System.out.print(numbers[i] + " ");
}
}
}
答
你没有实际交换的数字,其用户输入,你总是交换与1st
4th
元素。
要交换元素,您需要找出它们所属的索引。
public static int indexOf(int []arr, int ele)
{
for(int i = 0; i < arr.length; ++i)
if(arr[i] == ele)
return i;
return -1;
}
我们交换这些元素,调用这个函数。
int first = sc.nextInt();
int firstIndex = indexOf(arr, first);
int second = sc.nextInt();
int secondIndex = indexOf(arr, second);
int temp;
temp = arr[firstIndex];
arr[firstIndex] = arr[secondIndex];
arr[secondIndex] = temp;
答
你为什么不试试这个。请记住,数组的下标0
import java.util.Scanner;
public class Swap2
{
public static void main(String []args)
{
Scanner keyboardIn = new Scanner (System.in);
int[] numbers = new int []{12,9,33,28,5};
int temp, first, second;
System.out.println ("Before the swap: ");
for(int i=0; i < numbers.length; i++)
{
System.out.print(numbers[i] + " ");
}
System.out.println();
System.out.println ("Enter the first number to swap:");
first = keyboardIn.nextInt();
System.out.println ("Enter the second number to swap:");
second = keyboardIn.nextInt();
System.out.println();
temp = numbers[first];
numbers [first] = numbers [second];
numbers [second] = temp;
System.out.println ("After the swap:");
for (int i = 0; i < numbers.length; i++)
{
System.out.print (numbers[i] + " ");
}
}
}
+0
感谢您的帮助。 – Ant695
是啊,这一点从前面的问题这是交换第1个要素与第4,而遗留下来的我试图找出如何让用户输入元素交换。 – Ant695
@ Ant695所以你就是这么做的:P –
谢谢,这真的很有帮助。 – Ant695