JQuery获取#只有链接
问题描述:
由于某种原因,我的变量$ startwith只是获取home.php而不是以'#'开头的链接(eg.href =“#A”)... This是我的JQuery形式JQuery获取#只有链接
<ul>
<li><a href="home.php">Home</a></li>
<li class="dropdown"><a href="authors.php">Authors</a>
<div class="dropdown-content">
<a href="viewAuthor.php">View Author Profile</a>
</li>
<li class="dropdown"><a href="books.php">Books</a>
<div class="dropdown-content">
<a href="viewBookList.php">View Books</a>
</div>
</li>
<li class="dropdown"><a href="publishers.php">Publishers</a>
<div class="dropdown-content">
<a href="publishers.php">View Publishers</a>
<a href="addPublisher.php">Add Publisher</a>
</div>
</li>
<li class="dropdown"><a href="genres.php">Genres</a>
<div class="dropdown-content">
<a href="genres.php">View Genres</a>
<a href="addGenre.php">Add Genre</a>
</div>
</li>
<li><a href="signout.php">Sign Out</a>
<br>
</ul>
<br><br>
<script>
$(function() {
$("a[href^='#']").on('click', function() {
var sW = $('a').attr('href').replace("#", "");
$.get("getpublisher.php", {startsWith: sW})
.done(function (data) {
$('#listData').html(data);
});
});
});
</script>
<div align="center">
<a href="#A">A | </a>
<a href="#B">B | </a>
<a href="#C">C | </a>
<a href="#D">D | </a>
<a href="#E">E | </a>
<a href="#F">F | </a>
<a href="#G">G | </a>
<a href="#H">H | </a>
<a href="#I">I | </a>
<a href="#J">J | </a>
<a href="#K">K | </a>
<a href="#L">L | </a>
<a href="#M">M | </a>
<a href="#N">N | </a>
<a href="#O">O | </a>
<a href="#P">P | </a>
<a href="#Q">Q | </a>
<a href="#R">R | </a>
<a href="#S">S | </a>
<a href="#T">T | </a>
<a href="#U">U | </a>
<a href="#V">V | </a>
<a href="#W">W | </a>
<a href="#X">X | </a>
<a href="#Y">Y | </a>
<a href="#Z">Z | </a>
</div>
<div id="listData"></div>
getpublisher.php 在这种情况下,当我回声$ startWith,它让我home.php和我的查询将返回我一个0..Any知道如何改变?
$startsWith = $_GET['startsWith'];
$sql = "SELECT * FROM `publisher` WHERE publisher_name LIKE '"+$startsWith+"%' ORDER BY publisher_name ASC";
$r = mysqli_query($link, $sql);
$rowcount = mysqli_num_rows($r);
//echo $sql ;
if ($rowcount > 0) {
while ($row = mysqli_fetch_array($r, MYSQLI_ASSOC)) {
echo $row['publisher_name'] . "<br>";
}
} else {
echo "0 results";
}
答
在点击处理程序中,您需要点击元素的href。
var sW = $('a').attr('href').replace("#", "");
这将让第一<a>
标签的href在页面
更改为
var sW = $(this).attr('href').replace("#", "");
在事件处理器this
是事件发生
这是我的查询元素当我回应出来... SELECT * FROM'publisher' WHERE publisher_name LIKE'home.php%'ORDER BY publisher_name ASC –