苹果为什么不增加？

问题描述：

我正在尝试做这个小游戏，并且由于某种原因，当我在“您想选择一个苹果吗？”时输入“Y”？无论我尝试什么，IT都会停留在1。这里是我的代码：苹果为什么不增加？

import time 
global choice 
global gold 
global apples 
apples = 0 
gold = 0 

def begin(): 
    apples = 0 
    gold = 0 
    print ("Let's go!") 
    if gold > 99: 
     print ("You've won the game!") 
     play = input ("Do you want to play again? Please answer Y/N.") 
     if play == "Y": 
      begin() 
     if play == "N": 
      print ("Okay, bye then.") 
    pick = input ("Do you want to pick an apple Y/N?") 
    if pick == "Y": 
     print ("You pick an apple") 
     apples=apples+1 
     apples = 1 
     print ("You currently have,",apples," apples") 
     begin() 
    if pick == "N": 
     sell = input("Do you want to sell your apples Y/N?") 
     if sell == "Y": 
      gold 
      apples 
      print ("You currently have,",apples,"apples") 
      print("You have sold your apples") 
      gold=apples*10 
      print ("Your gold is now:",gold) 
      begin() 
      start() 

print ("Hello and welcome!") 
name = input("What's your name?") 
print ("Welcome, "+name+"!") 
print ("The goal of this game is to collect apples") 
print ("After you have collected these applaes, you sell them.") 
choice = input("Do you want to play? Type Y/N.") 
if choice == "Y": 
    begin() 
if choice == "N": 
    print ("Okay, bye then.")

如果有人可以帮助我解决这个问题，将不胜感激。我只是一个初学者，所以不要太苛刻。对不起，如果这个问题很明显，我才刚刚开始。

答

线后

苹果=苹果+ 1

你有线

苹果= 1

其复位苹果为1，使其显示您只有1个苹果。

答

您在代码的顶层有一堆global语句。那些什么都不做。如果要使用全局变量，则需要将global语句放入使用变量的函数中，以告诉Python使用该名称的全局变量而不是使用局部变量。

尝试：

apples = 0 # don't repeat these lines inside the function 
gold = 0 # (unless you want the variables to get reset each time you call it) 

def begin(): 
    global gold # move the global statements inside the function 
    global apples 

    # ...

的choice变量不出现在begin功能使用，所以你不需要为它global声明。

正如Dobellyo指出的那样，您在函数内的作业中也有一些杂乱的逻辑。您需要决定何时要增加现有值，以及何时要分配固定值。一个接一个地做这两件事通常是没有意义的。

苹果为什么不增加？

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