Python从循环返回所有项目？

Question

我想不出如何返回使用此代码的所有物品：

@staticmethod 
    def create_dataset(): 
     cols = Colleagues.get_all_colleagues() 
     cols_abs = ((col['Firstname'] + " " + col['Surname'], col['Absences']) for col in cols) 
     for col in cols_abs: 
      dataset = list() 
      sum_days = list() 
      for d in col[1]: 
       start_date = d[0] 
       end_date = d[1] 
       s = datetime.strptime(start_date, "%Y-%m-%d") 
       e = datetime.strptime(end_date, "%Y-%m-%d") 
       startdate = s.strftime("%b-%y") 
       days = numpy.busday_count(s, e) + 1 
       sum_days.append(days) 
       days_per_month = startdate, days 
       dataset.append(days_per_month) 
      dict_gen1 = dict(dataset) 
      comb_days = sum(sum_days) 
      dict_gen2 = {'Name': col[0], 'Spells': len(col[1]), 'Total(Days)': comb_days} 
      dict_comb = [{**dict_gen1, **dict_gen2}] 
      return dict_comb 

它只返回第一个“关口”。如果我在循环之外移动return语句，它将只返回我的数据集中的最后一个项目。这是从col_abs返回的输出：

('Jonny Briggs', [['2015-08-01', '2015-08-05'], ['2015-11-02', '2015-11-06'], ['2016-01-06', '2016-01-08'], ['2016-03-07', '2016-03-11']]) 
('Matt Monroe[['2015-12-08', '2015-12-11'], ['2016-05-23', '2016-05-26']]) 
('Marcia Jones', [['2016-02-02', '2016-02-04']]) 
('Pat Collins', []) 
('Sofia Marowzich', [['2015-10-21', '2015-10-30'], ['2016-03-09', '2016-03-24']]) 
('Mickey Quinn', [['2016-06-06', '2016-06-08'], ['2016-01-18', '2016-01-21'], ['2016-07-21', '2016-07-22']]) 
('Jenifer Andersson', []) 
('Jon Fletcher', []) 
('James Gray', [['2016-04-01', '2016-04-06'], ['2016-07-04', '2016-07-07']]) 
('Matt Chambers', [['2016-05-02', '2016-05-04']]) 

谁能帮助我更好地理解这种因为我想返回“dict_comb”在col_abs每个条目？

Answer 1

用yield声明替换您的return声明。这将允许您的方法在每次迭代后“屈服”或返回值时继续循环。