在运行python3代码时在Hackerearth上运行时出错NZEC

Question

当我在hackerearth上运行下面的代码时，它给了我运行时错误NZEC。

t = input() 
vow = ["A","a","E","e","I","i","O","o","U","u"] 
while t>0: 
    count_vow = 0 
    str1 = input() 
    for i in range(str1): 
     if i in vow: 
      count_vow += 1 
    print(count_vow) 
    t -= 1 

任何排序的帮助，将不胜感激。

Answer 1

你期待的第一个输入是一个数值，所以你应该换你input()呼叫在int()所以它存储这多项

你有第二个问题是，你叫for i in range(str1)的str1是一个字符串，使用range()是数字。只需使用for i in str1:

t = int(input()) 
vow = ["A","a","E","e","I","i","O","o","U","u"] 
while t > 0: 
    count_vow = 0 
    str1 = input() 
    for i in str1: 
     if i in vow: 
      count_vow += 1 
    print(count_vow) 
    t -= 1 


Test Cases: 
# >> denotes input and > denotes output 

>> 2 
>> nBBZLaosnm 
> 2 
>> JHkIsnZtTL 
> 1