Rock,Paper,Scissors- BlueJ crazy loop
问题描述:
以下是我在BlueJ的岩石,纸,剪刀游戏的代码。当我编译并且用户输入一个输入时,计算机立即从playerWins()打印大量输出。当用户键入“退出”时游戏结束。有人可以帮助我,让我的屏幕不会被淹没吗? (如果有什么方法可以压缩我的代码,那也会很棒)。Rock,Paper,Scissors- BlueJ crazy loop
import java.util.Random;
import java.util.Scanner;
public class RockPaperScissors
{
public static void main(String[] args)
{
int wins = 0, losses = 0, ties = 0;
boolean output;
Scanner scan = new Scanner(System.in);
System.out.print("(R)ock, (P)aper, (S)cissors, or quit: ");
String playerChoice = scan.nextLine();
while (playerChoice.equals("quit") == false)
{
playerChoice = playerChoice.toUpperCase();
String computerChoice = getComputerChoice();
if(playerChoice.equals(computerChoice) != true)
{
output = playerWins(playerChoice, computerChoice);
if (output == true)
{
wins++;
}
else if (output == false)
{
losses++;
}
}
else
{
ties++;
System.out.println("Tie!");
}
}
System.out.println("QUIT");
System.out.println("Wins: " + wins);
System.out.println("Losses: " + losses);
System.out.println("Ties: " + ties);
scan.close();
}
public static String getComputerChoice()
{
Random gen = new Random();
int num = gen.nextInt(30) + 1;
if (num % 3 == 2)
{
return "R";
}
else if (num % 3 == 1)
{
return "P";
}
else
{
return "S";
}
}
public static boolean playerWins(String playerChoice, String computerChoice)
{
if (playerChoice.equals("R") == true)
{
if (computerChoice.equals("P") == true)
{
System.out.println("My Point! \nP beats R"); // Rock is beaten by paper
return false;
}
else if (computerChoice.equals("S") == true)
{
System.out.println("Your Point! \nR beats S"); // Rock beats scissors
return true;
}
}
else if (playerChoice.equals("P") == true)
{
if (computerChoice.equals("R") == true)
{
System.out.println("Your Point! \nP beats R"); //Paper beats rock
return true;
}
else if (computerChoice.equals("S") == true)
{
System.out.println("My Point! \nS beats P"); //Paper is beaten by scissors
return false;
}
}
else if (playerChoice.equals("S") == true)
{
if (computerChoice.equals("P") == true)
{
System.out.println("Your Point! \nS beats P"); //Scissor beats paper
return true;
}
else if (computerChoice.equals("R") == true)
{
System.out.println("My Point! \nR beats S"); //Scissors is beaten by rock
return false;
}
}
return false;
}
}
答
这两条线是问题:
String playerChoice = scan.nextLine();
while (playerChoice.equals("quit") == false) {
您正在阅读一条线,然后检查该行一遍又一遍。您需要阅读循环内的新行。现在你已经拥有了它的方式,它只是试图一次又一次地做出同样的举动。
尝试:
String playerChoice = scan.nextLine();
while (playerChoice.equals("quit") == false) {
//do all of the stuff that is already inside your loop
playerChoice = scan.nextLine();
}
再处理最后一次输入后,每次这将让用户的输入。
答
要检查用户输入的只有一次,那就是在循环之前:要解决
String playerChoice = scan.nextLine();
一个非常好的方法如下:
String playerChoice;
while((playerChoice = scan.nextLine()).equals("quit") == false)
{
//more code
}
上面的代码做什么,那么在调用.equals("quit")
之前就设置了playerChoice
。如果你使用这种方法,你不需要在循环结尾设置更多的行来设置playerChoice
,但只需在循环的头部执行该操作即可。
在**''while'(playerChoice.equals(“quit”)== false)''''*''loop'中更新'playerChoice' **。 'playerChoice = scan.nextLine();' - 否则,无限循环而不提示另一个选择。 –
*“...帮助我,我的屏幕不会被淹没”*是什么意思?你能显示一些输出吗? – jww