试图打开一个串口。获取错误。什么导致了错误？

Question

我使用单声道和C＃打开我的电脑上的ttys2端口。我花了很多时间试图弄清楚为什么我无法打开我的串口。我终于包括一个尝试赶上，以帮助弄清楚。我是C＃的新手..所以任何指导都会有所帮助。

Button was just pushed .... Opening Port.... 
Error in Opening dev/ttys2 
System.IO.IOException: No such file or directory 
    at System.IO.Ports.SerialPortStream.ThrowIOException() [0x00012] in 
<f8255d9ef0594d18ae2c0d97286b9a80>:0 
at System.IO.Ports.SerialPortStream..ctor (System.String portName, 
System.Int32 baudRate, System.Int32 dataBits, System.IO.Ports.Parity 
parity, System.IO.Ports.StopBits stopBits, System.Boolean dtrEnable, 
System.Boolean rtsEnable, System.IO.Ports.Handshake handshake, 
System.Int32 readTimeout, System.Int32 writeTimeout, System.Int32 readBufferSize, System.Int32 writeBufferSize) [0x0001e] in <f8255d9ef0594d18ae2c0d97286b9a80>:0 
    at (wrapper remoting-invoke-with-check) 
    System.IO.Ports.SerialPortStream:.ctor (string,int,int,System.IO.Ports.Parity,System.IO.Ports.StopBits,bool,bool,System.IO.Ports.Handshake,int,int,int,int) 
    at System.IO.Ports.SerialPort.Open() [0x00078] in 
<f8255d9ef0594d18ae2c0d97286b9a80>:0 
    at (wrapper remoting-invoke-with-check) 
System.IO.Ports.SerialPort:Open() 
    at MonoSerial.Program.Main() [0x00089] in 
<805ba7595bb8403d9fb17ebbff143c7f>:0 

这里是我写的代码：

Console.WriteLine("Button was just pushed .... Opening Port...."); 
     SerialPort Serial_tty = new SerialPort(); 
     string ttyname; 
     ttyname = "dev/ttys2"; 


     Serial_tty.PortName = ttyname;   // assign the port name 
     Serial_tty.BaudRate = 9600;    // Baudrate = 9600bps 
     Serial_tty.Parity = Parity.None;  // Parity bits = none 
     Serial_tty.DataBits = 8;     // No of Data bits = 8 
     Serial_tty.StopBits = StopBits.One;  // No of Stop bits = 1 
     Serial_tty.Handshake = Handshake.None; 

try 
{ 
    Serial_tty.Open();     // Open the port  
    Serial_tty.Write("A");    // Write an ascii "A" 
    Serial_tty.Close();    // Close port 
    Console.WriteLine("\nA written to port {0}", Serial_tty.PortName); 
} 
catch(Exception e) 
{ 
    Console.WriteLine("Error in Opening {0}",Serial_tty.PortName); 
    Console.WriteLine(e); 
} 

Answer 1

ttyname = "dev/ttys2" 

我敢肯定你需要一个领导对文件名的前/，否则它会尝试打开该文件相对于当前目录，如home/pax/dev/ttys2。