roslyn项目配置
问题描述:
我正在使用Microsoft.CodeAnalysis和.MSBuild加载解决方案,它的项目和检索项目OutputFilePath。麻烦是调试和发布有不同的,我不能找出一种方法来切换解决方案配置。任何想法如何设置将使用哪种配置?roslyn项目配置
MSBuildWorkspace workspace = MSBuildWorkspace.Create();
workspace.LoadMetadataForReferencedProjects = true;
Solution solution = workspace.OpenSolutionAsync("someSolution.sln").Result;
foreach (Project project in solution.Projects)
Console.Out.WriteLine(project.OutputFilePath);
workspace.CloseSolution();
答
某些MSBuild属性(如通常的输出路径)取决于项目的构建配置。您在创建工作区时必须指定该配置。
例如:
var properties = new Dictionary<string, string>
{
{ "Configuration", "Debug" } // Or "Release", or whatever is known to your projects.
// ... more properties that could influence your property,
// e.g. "Platform" ("x86", "AnyCPU", etc.)
};
MSBuildWorkspace workspace = MSBuildWorkspace.Create(properties);
workspace.LoadMetadataForReferencedProjects = true;
Solution solution = workspace.OpenSolutionAsync("someSolution.sln").Result;
foreach (Project project in solution.Projects)
Console.Out.WriteLine(project.OutputFilePath);
workspace.CloseSolution();
尝试传递一个字典与条目'{ “配置”, “调试”}'(或 “释放”)到'MSBuildWorkspace.Create()'方法。 –
它的工作原理,谢谢! –
很高兴帮助。我有/没有电脑来验证它。把它变成一个有更多信息的答案。 –