通过HttpResponse下载Zip文件Java

Question

因此，我从数据库（各种mimetypes）抓取了一组blob，并试图将它们压缩成由用户通过http响应下载。我可以让下载发生，但是当我尝试打开下载的zip文件时，它会显示“存档文件格式未知或已损坏。”我尝试了下面的代码，使用application/zip，application/octet-stream和application/x-zip-compressed，但我开始认为问题在于我如何添加文件。我也在使用Java 7和Grails 2.2.4。

任何帮助，这将不胜感激。谢谢！

final ZipOutputStream out = new ZipOutputStream(new FileOutputStream("test.zip")); 


     for (Long id : ids){ 

      Object[] stream = inlineSamplesDataProvider.getAttachmentStream(id); 


      if (stream) { 

       String fileName = stream[0] 
       String mimeType = (String) stream[1]; 
       InputStream inputStream = stream[2] 
       byte[] byteStream = inputStream.getBytes(); 

       ZipEntry zipEntry = new ZipEntry(fileName) 
       out.putNextEntry(zipEntry); 
       out.write(byteStream, 0, byteStream.length); 
       out.closeEntry(); 
      } 
     } 

     out.close(); 
     response.setHeader("Content-Disposition", "attachment; filename=\"" + "test.zip" + "\""); 
     response.setHeader("Content-Type", "application/zip"); 
     response.outputStream << out; 
     response.outputstream.flush(); 

Answer 1

我在这里找到了答案：Returning ZipOutputStream to browser

好吧，那又怎样结束了工作对我来说是转换ZipOutputStream到一个ByteArrayOutputStream并将其写入为一个byte []回应：

 ByteArrayOutputStream baos = new ByteArrayOutputStream(); 
     final ZipOutputStream out = new ZipOutputStream(baos); 

     Calendar cal = Calendar.getInstance(); 
     String date = new SimpleDateFormat("MMM-dd").format(cal.getTime()); 

     final String zipName = "COA_Images-" + date + ".zip"; 



     for (Long id : ids){ 

      Object[] stream = inlineSamplesDataProvider.getAttachmentStream(id); 


      if (stream) { 

       String fileName = stream[0] 
       String mimeType = (String) stream[1]; 
       InputStream inputStream = stream[2] 
       byte[] byteStream = inputStream.getBytes(); 

       ZipEntry zipEntry = new ZipEntry(fileName) 
       out.putNextEntry(zipEntry); 
       out.write(byteStream, 0, byteStream.length); 
       out.closeEntry(); 
      } 
     } 

     out.close(); 

     response.setHeader("Content-Disposition", "attachment; filename=\"" + zipName + "\""); 
     response.setHeader("Content-Type", "application/zip"); 
     response.getOutputStream().write(baos.toByteArray()); 
     response.flushBuffer(); 
     baos.close(); 

感谢大家帮助！