如何计算距给定日期X个星期几的日期？

Question

我能够在我输入的任何日期添加102天，但现在的问题是，它应该是102 周天（不包括周末）。我怎样才能做到这一点？

这里是我的代码只是增加102天：

private void txtStartKeyReleased(java.awt.event.KeyEvent evt) { 
    try {  
     Date date1 = new SimpleDateFormat("yyyy-MM-dd").parse(txtStart.getText()); 

     SimpleDateFormat sdf = new SimpleDateFormat("yyyy-MM-dd");  
     Calendar cal = Calendar.getInstance(); 
     cal.setTime(date1); 
     cal.add(Calendar.DATE, 102); 
     String expDateString = sdf.format(cal.getTime()); 
     txtExpiry.setText(expDateString); 
    } catch (ParseException ex) { 
     Logger.getLogger(ClientInfo.class.getName()).log(Level.SEVERE, null, ex); 
    } 
} 

Answer 1

这应该添加weekdays工作日（周末被忽略）上的日期。如果您通过0获得weekdays，它将获得下一个工作日。那么，Saturday + 1 weekday = Tuesday。

private static Date addWeekdaysToDate(Date date, int weekdays) { 
    Calendar cal = Calendar.getInstance(); 
    cal.setTime(date); 
    int originalDayOfWeek = cal.get(Calendar.DAY_OF_WEEK); 
    int numWeeks = weekdays/5; 
    int remainderDays = weekdays % 5; 
    cal.add(Calendar.DAY_OF_MONTH, numWeeks * 7 + remainderDays); 

    int adjustmentDays = 0; 
    if (originalDayOfWeek == Calendar.SUNDAY) { 
     adjustmentDays = 1; 
    } else if (originalDayOfWeek + remainderDays > Calendar.FRIDAY) { 
     adjustmentDays = 2; 
    } 
    cal.add(Calendar.DAY_OF_MONTH, adjustmentDays); 
    return cal.getTime(); 
} 

编辑：

在你的代码，只需替换为以下：

private static Date addWeekdaysToDate(Date date, int weekdays) { 
    Calendar cal = Calendar.getInstance(); 
    cal.setTime(date); 
    int originalDayOfWeek = cal.get(Calendar.DAY_OF_WEEK); 
    int numWeeks = weekdays/5; 
    int remainderDays = weekdays % 5; 
    cal.add(Calendar.DAY_OF_MONTH, numWeeks * 7 + remainderDays); 

    int adjustmentDays = 0; 
    if (originalDayOfWeek == Calendar.SUNDAY) { 
     adjustmentDays = 1; 
    } else if (originalDayOfWeek + remainderDays > Calendar.FRIDAY) { 
     adjustmentDays = 2; 
    } 
    cal.add(Calendar.DAY_OF_MONTH, adjustmentDays); 
    return cal.getTime(); 
} 

private static SimpleDateFormat inputDateFormat = new SimpleDateFormat("yyyy-MM-dd"); 
private void txtStartKeyReleased(java.awt.event.KeyEvent evt) { 
    try { 
     txtExpiry.setText(
      inputDateFormat.format(
       addWeekdaysToDate(inputDateFormat.parse(txtStart.getText()), 102) 
      ) 
     ); 
    } catch (ParseException ex) { 
     Logger.getLogger(ClientInfo.class.getName()).log(Level.SEVERE, null, ex); 
    } 
} 

Answer 2

怎么样以下？

for (int i = 1; i <= 102; i++) 
{ 
    DateTime thisOne = DateTime.Parse("2012-03-13"); 

    string thisDay = thisOne.ToString("dddd"); 

    if (thisDay != "Saturday" && thisDay != "Sunday") 
    { 
     cal.add(Calendar.DATE, i); 
    } 
} 

编辑：更新了自定义日期

Answer 3

我只是将代码粘贴片，其单独排除周末。请使用这个根据你的目的

int numberOfDays = 102; 
int count = 1; 
String expDateString = null; 
Date temp = date1; 
while(count != numberOfDays){ 
    SimpleDateFormat sdf = new SimpleDateFormat("yyyy-MM-dd");  
    Calendar cal = Calendar.getInstance(); 
    cal.setTime(temp); 
    int dayOfWeek = cal.get(Calendar.DAY_OF_WEEK); 
    if(!(dayOfWeek == Calendar.SATURDAY || dayOfWeek == Calendar.SUNDAY)){ 
     cal.add(Calendar.DATE, count); 
     count++; 
    } 
    temp = cal.getTime(); 
    expDateString = sdf.format(cal.getTime()); 
}