如何在不创建ZIP文件的情况下在Android中创建ZIP InputStream？

问题描述：

我在Android应用程序使用NanoHTTPD作为Web服务器，希望压缩某些文件并创建在服务器端的InputStream，我使用代码A.如何在不创建ZIP文件的情况下在Android中创建ZIP InputStream？

我在How to zip and unzip the files?阅读代码B下载客户端InputStream的，但如何在不创建ZIP文件的情况下在Android中创建ZIP InputStream？我不认为Code C是好的方法，因为它首先制作ZIP文件，然后将ZIP文件转换为FileInputStream，我希望直接创建一个ZIP InputStream！

代码A

private Response ActionDownloadSingleFile(InputStream fis) {  
    Response response = null; 
    response = newChunkedResponse(Response.Status.OK, "application/octet-stream",fis); 
    response.addHeader("Content-Disposition", "attachment; filename="+"my.zip"); 
    return response; 
}

代码B

public static void zip(String[] files, String zipFile) throws IOException { 
    BufferedInputStream origin = null; 
    ZipOutputStream out = new ZipOutputStream(new BufferedOutputStream(new FileOutputStream(zipFile))); 
    try { 
     byte data[] = new byte[BUFFER_SIZE]; 

     for (int i = 0; i < files.length; i++) { 
      FileInputStream fi = new FileInputStream(files[i]);  
      origin = new BufferedInputStream(fi, BUFFER_SIZE); 
      try { 
       ZipEntry entry = new ZipEntry(files[i].substring(files[i].lastIndexOf("/") + 1)); 
       out.putNextEntry(entry); 
       int count; 
       while ((count = origin.read(data, 0, BUFFER_SIZE)) != -1) { 
        out.write(data, 0, count); 
       } 
      } 
      finally { 
       origin.close(); 
      } 
     } 
    } 
    finally { 
     out.close(); 
    } 
}

代码C

File file= new File("my.zip"); 
FileInputStream fis = null; 
try 
{ 
    fis = new FileInputStream(file); 
} catch (FileNotFoundException ex) 
{ 

}

您需要在服务器中创建一个*输出*流。一个'ZipOutputStream'，围绕着服务器技术给你的任何输出流。 – EJP

谢谢！对于EJP，你能给我一些示例代码吗？ – HelloCW

由于ZipInputSteam扩展了FilterInputStream，所以不能直接制作ZipInputSteam，所以它基本上起到了包装类的作用，它为流读取zip文件提供了功能。你需要像'new ZipInputStream（new FileInputStream（zipFile））' –

答

紫pInputStream按照文档ZipInputStream

ZipInputStream是用于读取ZIP文件格式的文件的输入流过滤器。包括对压缩和未压缩条目的支持。

早些时候，我以一种不可能使用ZipInputStream的方式回答了这个问题。对不起。

但投资一段时间，我发现，有可能按下面的代码

这是非常明显的后因为你是在zip格式在网络上发送文件。

//Create proper background thread pool. Not best but just for solution 
new Thread(new Runnable() { 
    @Override 
    public void run() { 

    // Moves the current Thread into the background 
    android.os.Process.setThreadPriority(android.os.Process.THREAD_PRIORITY_BACKGROUND); 

    HttpURLConnection httpURLConnection = null; 
    byte[] buffer = new byte[2048]; 
    try { 
     //Your http connection 
     httpURLConnection = (HttpURLConnection) new URL("https://s3-ap-southeast-1.amazonaws.com/uploads-ap.hipchat.com/107225/1251522/SFSCjI8ZRB7FjV9/zvsd.zip").openConnection(); 

     //Change below path to Environment.getExternalStorageDirectory() or something of your 
     // own by creating storage utils 
     File outputFilePath = new File ("/mnt/sdcard/Android/data/somedirectory/"); 

     ZipInputStream zipInputStream = new ZipInputStream(new BufferedInputStream(httpURLConnection.getInputStream())); 
     ZipEntry zipEntry = zipInputStream.getNextEntry(); 

     int readLength; 

     while(zipEntry != null){ 
     File newFile = new File(outputFilePath, zipEntry.getName()); 

     if (!zipEntry.isDirectory()) { 
      FileOutputStream fos = new FileOutputStream(newFile); 
      while ((readLength = zipInputStream.read(buffer)) > 0) { 
      fos.write(buffer, 0, readLength); 
      } 
      fos.close(); 
     } else { 
      newFile.mkdirs(); 
     } 

     Log.i("zip file path = ", newFile.getPath()); 
     zipInputStream.closeEntry(); 
     zipEntry = zipInputStream.getNextEntry(); 
     } 
     // Close Stream and disconnect HTTP connection. Move to finally 
     zipInputStream.closeEntry(); 
     zipInputStream.close(); 
    } catch (IOException e) { 
     e.printStackTrace(); 
    }finally { 
     // Close Stream and disconnect HTTP connection. 
     if (httpURLConnection != null) { 
     httpURLConnection.disconnect(); 
     } 
    } 
    } 
}).start();

@HelloCW让我知道你是否尝试过，因为它工作正常，根据所需的输出。然而，它在结束流方面需要稍微优化。 –

如何在不创建ZIP文件的情况下在Android中创建ZIP InputStream？

相关推荐