来自输入表单的foreach值
问题描述:
请帮助我。我的代码有问题。来自输入表单的foreach值
这是代码input.php:
<form method="POST" action="simpan.php">
NIM : <input type="text" required placeholder="input NIM" name="nim"/><br/>
Name : <input type="text" required placeholder="input name" name="nama"/><br/>
score : <input type="number" required placeholder="input score between 0-100" name="score"/><br/><input type="submit" value="OK"/>
这是代码simpan.php:
<?php
session_start();
$_SESSION['nim'][] = $_POST['nim'];
$_SESSION['nama'][] = $_POST['nama'];
$_SESSION['nilai'][] = $_POST['score'];
header("location:index.php")
?>
和这是代码show.php:
<?php
session_start();
foreach($_SESSION as $key)
{
foreach($key as $data => $value)
{
echo "NIM : ",$value." ", "Name : ",$value." ", "Score : ",$value." ";
}
}
?>
结果: enter image description here 而问题是我想用窗体显示输入在 稔: 名称: 评分:
例如=净息差:01名:约翰得分:90
我应该在show.php改变,以便按照上面的格式出现? 谢谢:)
答
@Arif毛拉只是改变你的show.php喜欢下面希望这是你想要什么:
<?php
session_start();
$echoString = "";
foreach($_SESSION as $key => $sessionArr){
if($key == "nama"){
$echoString .= "name : ";
}
else if($key == "nilai"){
$echoString .= "score : ";
}
else{
$echoString .= $key." : ";
}
foreach($sessionArr as $value)
{
$echoString .= $value." ";
}
}
echo $echoString;
?>
答
请检查下面的例子中,我没有https://3v4l.org/CcOOK
<?php
$_POST['nim'] = 'Hrllo';
$_POST['nama'] = 'Data';
$_POST['score'] = '33';
$_SESSION['nim'][] = $_POST['nim'];
$_SESSION['nama'][] = $_POST['nama'];
$_SESSION['score'][] = $_POST['score'];
$string = '';
foreach($_SESSION as $main_key => $key)
{
foreach($key as $data => $value)
{
$string .= $main_key . ":" . $value . ' ';
}
}
$string = rtrim($string, ' ');
echo $string;
+0
如果输出结果如下= HIM:Hrllo nama:数据得分:33 –
+0
@ArifMaulana更新了答案 –
'回声$ value,“”;'应该是'echo $ value。“”;' –
你没有收到echo $ value的错误,“”;线。试着改变上面提到的评论。 – webpic
逗号工作连接也不是吗?你能告诉我们你的输出是什么样子吗? – Jamin