如何在matlab中显示40 gabor滤波器
问题描述:
有人可以帮助我如何在matlab中显示gabor滤波器,我可以显示它但它不是我想要的。这是我的代码:如何在matlab中显示40 gabor滤波器
[Gf,gabout] = gaborfilter1(B,sx,sy,f,theta(j));
G{m,n,i,j} = Gf;
,这是Gabor滤波器类:
function [Gf,gabout] = gaborfilter(I,Sx,Sy,f,theta);
if isa(I,'double')~=1
I = double(I);
end
for x = -fix(Sx):fix(Sx)
for y = -fix(Sy):fix(Sy)
xPrime = x * cos(theta) + y * sin(theta);
yPrime = y * cos(theta) - x * sin(theta);
Gf(fix(Sx)+x+1,fix(Sy)+y+1) = exp(-.5*((xPrime/Sx)^2+(yPrime/Sy)^2))*cos(2*pi*f*xPrime);
end
end
Imgabout = conv2(I,double(imag(Gf)),'same');
Regabout = conv2(I,double(real(Gf)),'same');
gabout = sqrt(Imgabout.*Imgabout + Regabout.*Regabout);
然后,我imshow与此代码:
imshow(G{m,n,i,j},[]);
,结果:
但我想要这个结果,有人可以帮我解决这个问题吗?
答
使用下面的功能。我希望这是有用的。
------------------------------------------------ ----------------
gfs = GaborFilter(51,0.45,0.05,6,4);
n=0;
for s=1:6
for d=1:4
n=n+1;
subplot(6,4,n)
imshow(real(squeeze(gfs(s,d,:,:))),[])
end
end
Sample Image
------------------------ ----------------------------------------
function gfs = GaborFilter(winLen,uh,ul,S,D)
% gfs(SCALE, DIRECTION, :, :)
winLen = winLen + mod(winLen, 2) -1;
x0 = (winLen + 1)/2;
y0 = x0;
if S==1
a = 1;
su = uh/sqrt(log(4));
sv = su;
else
a = (uh/ul)^(1/(S-1));
su = (a-1)*uh/((a+1)*sqrt(log(4)));
if D==1
tang = 1;
else
tang = tan(pi/(2*D));
end
sv = tang * (uh - log(4)*su^2/uh)/sqrt(log(4) - (log(4)*su/uh)^2);
end
sx = 1/(2*pi*su);
sy = 1/(2*pi*sv);
coef = 1/(2*pi*sx*sy);
gfs = zeros(S, D, winLen, winLen);
for d = 1:D
theta = (d-1)*pi/D;
for s = 1:S
scale = a^(-(s-1));
gab = zeros(winLen);
for x = 1:winLen
for y = 1:winLen
X = scale * ((x-x0)*cos(theta) + (y-y0)*sin(theta));
Y = scale * (-(x-x0)*sin(theta) + (y-y0)*cos(theta));
gab(x, y) = -0.5 * ((X/sx).^2 + (Y/sy).^2) + (2*pi*1j*uh)*X ;
end
end
gfs(s, d, :, :) = scale * coef * exp(gab);
end
end
答
将“ cos“分量 - >complex(0, (2*pi*f*xprime))
ans还将公式乘以比例因子(1/sqrt(2*Sy*Sx))
。
我认为您需要发布更多代码才能提供帮助。例如,您显示'gaborfilter'功能,但不显示'gaborfilter1'功能。他们是一样的吗?我假设你正在循环中运行'gaborfilter1',你可以发布该代码吗?我也怀疑你的Gabor滤波器的公式是错误的。西格玛在哪里?你打算做什么? – Tokkot 2013-10-03 17:04:46