C++如何从一个整数值中获取三个单独的日期值（日，月，年）

Question

好的，我以（yyyy/mm/dd）的格式询问用户的日期，然后在这种情况下下降到函数dateSplit。我知道自从我知道它总能成为我可以模拟它的前四位数字之后，我该如何做到这一年。任何人都知道的方式做一个月，这里的天是我到目前为止的代码：

void dateSplit(int date, int& year, int& day, int& mon) 
{ 
    // date % 10000 is a floating point value but i put it into an int to cut the back off 
    date % 10000 = year; 

} 

有谁明白，我怎么可以只读取中间的两个数字，最后两个？

想我会把我的主要代码，让别人能看到全貌：

int main() 
{ 
    // Variable Declarations 
    string airportCode, lat, longitude, timeZone; 
    int date; 
    char contin = 'Y'; 
    while (contin == 'Y' || contin == 'y') 
    { 
     // Ask User for Airport Code 
     cout << "Please Enter an Airport Code: "; 
     cin >> airportCode; 

     //Call to retrieve information 
     retrieveFromFile(airportCode, lat, longitude, timeZone); 

     //Call for date 
     cout << endl << "Please Enter a date(yyyy/mm/dd): "; 
     cin >> date; 

     // Continue running program? 
     cout << endl << "Would you like to continue? (Y/N): "; 
     cin >> contin; 

    } 
} 

这是终于做到了代码：

 void dateSplit(int date, int& year, int& day, int& mon) 
    { 
     // Ex. if date is 20150623, then it takes that number 
     // moves the decimal place over four digits 
     // then cuts off after the decimal point 
     // leaving just the first four digits 
     year = date/10000; 
     date %= 10000; 
     mon = date/100; 
     day = date % 100; 




     cout << endl << "Year: " << year 
      << endl << "Day : " << day 
      << endl << "Month:" << mon; 

    } 

Answer 1

只需使用部门和modulos砍它起来，像这样：

year = date % 10000; 
date /= 10000; 
month = date % 100; 
day = date/100;