防止每次显示选择器对话框获取用户帐户

防止每次显示选择器对话框获取用户帐户

问题描述:

我需要检查我的应用程序中的用户帐户,我需要检查它不止一次的应用程序,我用this answer和工作正常,但问题是每次我想要得到帐户选择器对话框出现“选择一个帐户”,它不是很好,我很欣赏任何解决方案!防止每次显示选择器对话框获取用户帐户

您使用的帐户选择器,所以你不应该指望没有出现该对话框

使用共享首选项存储检查值,然后检查它是否存在然后dnt显示是否不显示。

设定值偏好:

// MY_PREFS_NAME - a static String variable like: 
//public static final String MY_PREFS_NAME = "MyPrefsFile"; 
SharedPreferences.Editor editor = getSharedPreferences(MY_PREFS_NAME, MODE_PRIVATE).edit(); 
editor.putString("name", "user1"); 
editor.putInt("idName", 1); 
editor.commit(); 

检索数据从偏好:

SharedPreferences prefs = getSharedPreferences(MY_PREFS_NAME, MODE_PRIVATE); 
String restoredText = prefs.getString("text", null); 
if (restoredText != null) { 
    String name = prefs.getString("name", "No name defined");//"No name defined" is the default value. 
    int idName = prefs.getInt("idName", 0); //0 is the default value. 
} 




//Call this function in you OnCreate Method.! 
private void signIn() { 
     Intent signInIntent = Auth.GoogleSignInApi.getSignInIntent(mGoogleApiClient); 
     startActivityForResult(signInIntent, RC_SIGN_IN); 
    } 


    private void handleSignInResult(GoogleSignInResult result) { 
     Log.d(TAG, "handleSignInResult:" + result.isSuccess()); 
     if (result.isSuccess()) { 
      // Signed in successfully, show authenticated UI. 
      GoogleSignInAccount acct = result.getSignInAccount(); 

      Log.e(TAG, "display name: " + acct.getDisplayName()); 

      personName = acct.getDisplayName(); 
      email = acct.getEmail(); 

      if(acct.getPhotoUrl()!= null) { 
       personPhotoUrl = acct.getPhotoUrl(); 

      } 
      else 
      { 
       personPhotoUrl=Uri.parse("android.resource://com.compscitutorials.basigarcia.navigationdrawervideotutorial/drawable/add_profile_image");; 
       Log.d(TAG, "handleSignInResult: Photo Url is empty"); 
      } 



      Log.e(TAG, "Name: " + personName + ", email: " + email 
        + ", Image: " + personPhotoUrl.getPath().toString()); 

//   txtName.setText(personName); 
//   txtEmail.setText(email); 
//   Glide.with(getApplicationContext()).load(personPhotoUrl) 
//     .thumbnail(0.5f) 
//     .crossFade() 
//     .diskCacheStrategy(DiskCacheStrategy.ALL) 
//     .into(imgProfilePic); 
       updateUI(true); 


     } else { 
      // Signed out, show unauthenticated UI. 
      updateUI(false); 
     } 
    } 

现在您的当前用户与以前相比!

private void updateUI(boolean isSignedIn) { 
     if (isSignedIn) { 
    if(!currentName.equals(name)) 
    { 
    //Next, launch the account chooser intent: 

    Intent intent = AccountPicker.newChooseAccountIntent(null, null, 
     new String[]{GoogleAuthUtil.GOOGLE_ACCOUNT_TYPE}, 
     false, null, null, null, null); 

    try { 
     startActivityForResult(intent, REQUEST_CODE_EMAIL); 
    } catch (ActivityNotFoundException e) { 
     // This device may not have Google Play Services installed. 
     // TODO: do something else 
     } 
     } 
     } else { 
    //  Display Toast SignUp Failed 
       Toast.makeText(this, "SignUp Error", Toast.LENGTH_SHORT).show(); 
      } 
     } 

//最后,覆盖onActivityResult获得帐户类型和帐户名称:

@ @Override 
public void onActivityResult(int requestCode, int resultCode, Intent data) { 
    super.onActivityResult(requestCode, resultCode, data); 

    // Result returned from launching the Intent from GoogleSignInApi.getSignInIntent(...); 
    if (requestCode == RC_SIGN_IN) { 
     GoogleSignInResult result = Auth.GoogleSignInApi.getSignInResultFromIntent(data); 
     handleSignInResult(result); 
    } 
} 
+0

我需要控制如果保存的用户(上次选中的用户)与运行应用程序的用户是同一用户,那就是为什么我需要每次都检查一次,但不要每次都选择 – sasan

+0

,然后将您当前的用户与之前检查过的用户进行比较。如果相同,则显示是否显示。 –

+0

这就是问题所在!当我想要获得当前用户时出现选择器。我需要的是如何在获取用户时不显示? – sasan