返回任务方法的JSON错误消息
我创建了一个ASP.NET Web API,它将调用java web服务并在JSON中显示一些结果。当java web服务未运行时,我收到错误消息:返回任务<IHttpActionResult>方法的JSON错误消息
{“Message”:“发生错误。”,“ExceptionMessage”:“方法或操作未实现。”, C:\ Users \ attsuap1 \ Desktop \ Server Project \ ApiClientJavaWebService \ ApiClientJavaWebService \ Models \ RestfulClient.cs中的ApiClientJavaWebService.Models.RestfulClient.InternalServerError(异常例外)中的“ExceptionType”:“System.NotImplementedException”,“StackTrace”在C:\ Users \ attsuap1 \ Desktop \ Server Project \ ApiClientJavaWebService \ ApiClientJavaWebService \ Models \ RestfulClient.cs中的ApiClientJavaWebService.Models.RestfulClient.d__3.MoveNext()中的第43行\ r \ n:第36行\ r \ n ---从抛出异常的上一个位置结束堆栈跟踪--- System.Runtime.CompilerServices.TaskAwaiter.ThrowForNonSuccess(任务任务)中的\ r \ n \ System.Runtim中的\ r \ n e.CompilerServices.TaskAwaiter.HandleNonSuccessAndDebuggerNotification(任务任务)\ r \ n在System.Runtime.CompilerServices.TaskAwaiter 1.GetResult()\ r \ n在ApiClientJavaWebService.Controllers.AdditionController.d__1.MoveNext()在C:\ Users \ attsuap1 \ Desktop \ Server Project \ ApiClientJavaWebService \ ApiClientJavaWebService \ Controllers \ AdditionController.cs:第20行\ r \ n ---从以前位置抛出异常的堆栈跟踪结束--- \ r \ n在System.Runtime.CompilerServices .TaskAwaiter.ThrowForNonSuccess(任务任务)\ r \ n在System.Threading.Tasks.TaskHelpersExtensions.d__3`1.MoveNext()\ r \ n System.Runtime.CompilerServices.TaskAwaiter.HandleNonSuccessAndDebuggerNotification(任务任务)\ r \ n ---从以前位置抛出异常的堆栈跟踪结束---在System.Runtime.CompilerServices.TaskAwaiter.ThrowForNonSuccess(任务任务)上的\ r \ n在System.Runtime.CompilerServices.TaskAwaiter.HandleNonSuccessAndDebuggerNotification(任务任务)\ r \ n在System.Web.Http.Controllers.ApiControl lerActionInvoker.d__0.MoveNext()\ r \ n ---从之前的位置抛出异常的堆栈跟踪结束--- \ r \ n在System.Runtime.CompilerServices.TaskAwaiter.ThrowForNonSuccess(任务任务)\ r \ n System.Web.Http.Controllers.ActionFilterResult.d__2.MoveNext()\ r \ n下System.Runtime.CompilerServices.TaskAwaiter.HandleNonSuccessAndDebuggerNotification(任务任务)\ r \ n ---以前位置的堆栈跟踪结束,其中异常在System.Web的System.Runtime.CompilerServices.TaskAwaiter.HandleNonSuccessAndDebuggerNotification(任务任务)\ r \ n处,System.Runtime.CompilerServices.TaskAwaiter.ThrowForNonSuccess(任务任务)\ r \ n处抛出--- \ r \ n。 Http.Dispatcher.HttpControllerDispatcher.d__1.MoveNext()“}
我要如何改变这种去显示为{"The server is not running."}
错误信息?
这里是我的代码:
AdditionClient.cs
public class RestfulClient
{
private static HttpClient client;
private static string BASE_URL = "http://localhost:8080/";
static RestfulClient()
{
client = new HttpClient();
client.BaseAddress = new Uri(BASE_URL);
client.DefaultRequestHeaders.Accept.Add(
new MediaTypeWithQualityHeaderValue("application/json"));
}
public async Task<string> addition(int firstNumber, int secondNumber)
{
try
{
var endpoint = string.Format("addition/{0}/{1}", firstNumber, secondNumber);
var response = await client.GetAsync(endpoint);
return await response.Content.ReadAsStringAsync();
}
catch (Exception e)
{
}
return null;
}
}
AdditionController.cs
public class AdditionController : ApiController
{
private RestfulClient restfulClient = new RestfulClient();
public async Task<IHttpActionResult> Get(int firstNumber, int secondNumber)
{
var result = await restfulClient.addition(firstNumber, secondNumber);
var resultDTO = JsonConvert.DeserializeObject<Temp>(result);
return Json(resultDTO);
}
}
有人请你帮帮我。提前谢谢你。
我已经达到了我想要的。我意识到try catch方法应该在控制器类中而不是AdditionClient.cs类中。
这里是我的编辑类:
AdditionClient.cs
public class RestfulClient
{
private static HttpClient client;
private static string BASE_URL = "http://localhost:8080/";
static RestfulClient()
{
client = new HttpClient();
client.BaseAddress = new Uri(BASE_URL);
client.DefaultRequestHeaders.Accept.Add(
new MediaTypeWithQualityHeaderValue("application/json"));
}
public async Task<string> addition(int firstNumber, int secondNumber)
{
var endpoint = string.Format("addition/{0}/{1}", firstNumber, secondNumber);
var response = await client.GetAsync(endpoint);
return await response.Content.ReadAsStringAsync();
}
}
AdditionController.cs(聚焦在尝试捕捉部分)
try
{
var result = await restfulClient.addition(firstNumber, secondNumber);
var resultDTO = JsonConvert.DeserializeObject<Temp>(result);
return Json(resultDTO);
}
catch (Exception e)
{
var result = @"Server is down";
return Ok(new { ErrorMessage = result });
}
,这将是结果当服务器没有运行时,在浏览器上显示的是{"ErrorMessage":"Server is down"}
。
我想,你不能管理抛出你想要拉动数据的服务器的异常消息。那么,为什么不过滤这个异常呢?
try
{
var endpoint = string.Format("addition/{0}/{1}", firstNumber, secondNumber);
var response = await client.GetAsync(endpoint);
return await response.Content.ReadAsStringAsync();
}
catch (Exception e)
{
if (e.InnerException.Message == "The method or operation is not implemented")
{
//Do something
}
}
嗨谢谢你帮助我,是的我不能管理抛出异常消息,我想从中拉数据的服务器。我应该做些什么//做些什么? –
我对此很新,我以前没有这样做过。根据我研究的内容,我尝试了代码,如'返回内容(HttpStatusCode.BadRequest,“服务器不运行”);''返回ResponseMessage(Request.CreateErrorResponse(HttpStatusCode.InternalServerError,“Server is not running”)); '但是所有这些都不起作用 –
如果抛出的异常是“服务器没有运行”,你应该怎么做。您可以将它登录到某个地方,或者将响应返回给客户端。如果应用程序具有通用错误处理机制,则抛出一个带有要显示的消息的异常。 – lucky
你得到'System.NotImplementedException'。只要找到,你扔它 – Backs