单引号里面双引号php
问题描述:
我正在更新我使用硬编码日期从使用常量从配置文件中使用的脚本。这是工作好,直到我得到了以下一点。单引号里面双引号php
原:
function getDestroyedRelationships($relation){
$owner_user_id = $_REQUEST['owner_user_id'];
$tableName = "";
if($relation=="friends"){
$tableName = "yst_twitter_following_relationships";
}else if($relation=="followers"){
$tableName = "yst_twitter_follower_relationships";
}else{
return false;
}
$twitters = NULL;
$stmt = ulPdoDb::Prepare('log', 'SELECT your_id FROM '.$tableName.' WHERE my_id=? AND updated_on<(SELECT MAX(updated_on) FROM '.$tableName.' WHERE my_id=?)');
if (!ulPdoDb::BindExec(
$stmt,
array( // output
&$twitters, 'lob'
),
array( // input
&$owner_user_id, 'int',
&$owner_user_id, 'int'
)
))
{
ul_db_fail();
return false;
}
if ($twitters = $stmt->fetchAll(PDO::FETCH_COLUMN))
{
return $twitters;
}
else
{
//echo "Nothing";
}
return $twitters;
}
正如你可以在上面看到的$表名具有表前缀“YST”定义。我想改变“YST”阅读:执行此操作时
'.TABLE_PREFIX'
不过,我得到以下错误:
You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near ''.TABLE_PREFIX.'_twitter_following_relationships (my_id, your_id, created_on, up'
我怀疑这是用单引号是旁边做双引号?
有什么建议吗? 感谢
答
假设TABLE_PREFIX是你在什么地方定义的常量,只是这样做:
$tableName = TABLE_PREFIX.'_twitter_following_relationships';
这是完美的!谢谢。我不确定它应该如何处理报价等......非常感谢 – BHWD