如何与公共密钥
问题描述:
结合不同的数组值我有一个这样的数组:如何与公共密钥
Array
(
[0] => Array
(
[minutesPlayed] => 0
[totalSecondsPlayed] => 0
[flagrantFouls] => 0
[foulsReceived] => 0
[blocksReceived] => 0
[plusMinus] => 0
[player] => Array
(
[playerId] => 830651
[firstName] => Walter
[lastName] => Tavares
[uniform] => 21
)
[fieldGoals] => Array
(
[made] => 0
[attempted] => 0
)
[freeThrows] => Array
(
[made] => 12
[attempted] => 4
)
[threePointFieldGoals] => Array
(
[made] => 0
[attempted] => 0
)
)
[1] => Array
(
[minutesPlayed] => 0
[totalSecondsPlayed] => 0
[flagrantFouls] => 0
[foulsReceived] => 0
[blocksReceived] => 0
[plusMinus] => 0
[player] => Array
(
[playerId] => 830651
[firstName] => John
[lastName] => Tavares
[uniform] => 22
)
[fieldGoals] => Array
(
[made] => 0
[attempted] => 0
)
[freeThrows] => Array
(
[made] => 12
[attempted] => 6
)
[threePointFieldGoals] => Array
(
[made] => 0
[attempted] => 0
)
)
[2] => Array
(
[minutesPlayed] => 0
[totalSecondsPlayed] => 0
[flagrantFouls] => 0
[foulsReceived] => 0
[blocksReceived] => 0
[plusMinus] => 0
[player] => Array
(
[playerId] => 830651
[firstName] => Adrian
[lastName] => Tavares
[uniform] => 23
)
[fieldGoals] => Array
(
[made] => 0
[attempted] => 0
)
[freeThrows] => Array
(
[made] => 0
[attempted] => 0
)
[threePointFieldGoals] => Array
(
[made] => 12
[attempted] => 8
)
)
[3] => Array
(
[minutesPlayed] => 0
[totalSecondsPlayed] => 0
[flagrantFouls] => 0
[foulsReceived] => 0
[blocksReceived] => 0
[plusMinus] => 0
[player] => Array
(
[playerId] => 830651
[firstName] => Adrian
[lastName] => Methue
[uniform] => 24
)
[fieldGoals] => Array
(
[made] => 0
[attempted] => 0
)
[freeThrows] => Array
(
[made] => 0
[attempted] => 0
)
[threePointFieldGoals] => Array
(
[made] => 0
[attempted] => 0
)
)
)
我希望它是这样的:
Array
(
[fieldGoals] => Array
[0](
[player_name]=>Walter Tavares
[playerId] => 830651
[made] => 0
[attempted] => 0
)
[1](
[player_name]=>John Tavares
[playerId] => 830651
[made] => 0
[attempted] => 0
)
[2](
[player_name]=>Adrian Tavares
[playerId] => 830651
[made] => 0
[attempted] => 0
)
[3](
[player_name]=>Adrian Methue
[playerId] => 830651
[made] => 0
[attempted] => 0
)
[freeThrows] => Array
[0](
[player_name]=>Walter Tavares
[playerId] => 830651
[made] => 12
[attempted] => 4
)
[1](
[player_name]=>John Tavares
[playerId] => 830651
[made] => 12
[attempted] => 6
)
[2](
[player_name]=>Adrian Tavares
[playerId] => 830651
[made] => 12
[attempted] => 8
)
[3](
[player_name]=>Adrian Methue
[playerId] => 830651
[made] => 0
[attempted] => 0
)
[threePointFieldGoals] => Array
[0](
[player_name]=>Walter Tavares
[playerId] => 830651
[made] => 0
[attempted] => 0
)
[1](
[player_name]=>John Tavares
[playerId] => 830651
[made] => 0
[attempted] => 0
)
[2](
[player_name]=>Adrian Tavares
[playerId] => 830651
[made] => 0
[attempted] => 0
)
[3](
[player_name]=>Adrian Methue
[playerId] => 830651
[made] => 0
[attempted] => 0
)
)
这是我做过什么,到目前为止:
foreach($myArr as $playerStatsKey=>$playerStatsArray){
if(!is_array($playerStatsArray)){
continue;
}
foreach($playerStatsArray as $playkey=>$playVal){
if(!is_array($playVal)){
continue;
}
if($playkey=='player'){
$playerInfo[$playkey]['made'] = $playVal['made'];
$playerInfo[$playkey]['attempted'] = $playVal['attempted'];
}
$arr[$playkey] = $playerInfo;
$arr[$playkey] = $playVal['made'];
$arr[$playkey] = $playVal['attempted'];
}
echo '<pre>' ;print_r($arr );
我只是想结合不同的数组值与共同的key.how我可以做到这一点吗?
答
你在这里。此功能会做你的任务:
function combinePlayers($array) {
$return_array = array();
foreach ($array as $element) {
//collect data for the new player object
$player = array(
'player_name' => $element['player']['firstName'] . ' ' . $element['player']['lastName'],
'playerId' => $element['player']['playerId']
);
foreach ($element as $key => $value) {
if (is_array($value) && $key != 'player') {
//collect the keys to build the structure of the $return_array
if (! array_key_exists($key, $return_array)) {
$return_array[ $key ] = array();
}
//collect the returning values from the input array
array_push($return_array[ $key ], array_merge($value, $player));
}
}
}
return $return_array;
}
此功能遍历输入数组,并收集了哪些不是玩家信息的阵列值。同样在迭代中,它会创建一个新的玩家对象,它将合并为所有值。
答
Try like this..
It will return the combined result array as you want. I hope this will help.
foreach($myArr as $playerStatsKey=>$playerStatsArray){
$arr['fieldGoals'][] = array(
'player_name'=>$playerStatsArray['player']['firstName']." ".$playerStatsArray['player']['lastName'],
'playerId'=>$playerStatsArray['player']['playerId'],
'made'=>$playerStatsArray['fieldGoals']['made'],
'attempted'=>$playerStatsArray['fieldGoals']['attempted']
);
$arr['freeThrows'][] = array(
'player_name'=>$playerStatsArray['player']['firstName']." ".$playerStatsArray['player']['lastName'],
'playerId'=>$playerStatsArray['player']['playerId'],
'made'=>$playerStatsArray['freeThrows']['made'],
'attempted'=>$playerStatsArray['freeThrows']['attempted']
);
$arr['threePointFieldGoals'][] = array(
'player_name'=>$playerStatsArray['player']['firstName']." ".$playerStatsArray['player']['lastName'],
'playerId'=>$playerStatsArray['player']['playerId'],
'made'=>$playerStatsArray['threePointFieldGoals']['made'],
'attempted'=>$playerStatsArray['threePointFieldGoals']['attempted']
);
}
echo '<pre>' ;print_r($arr);
使用array_merge – aldrin27
我没有两个不同的数组。我想根据一些关键字分开数组,因为我在我的问题中询问 – Rahul