弹簧数据jpa和多个集合的条件

Question

我想通过一个所有应该匹配的列表。

@Query("select g.name as name FROM Gym g " + 
      "LEFT JOIN g.listOfEquipment listOfEquipment " + 
      "WHERE " + 
      "(((:listOfEquipment) is null) or listOfEquipment.id in (:listOfEquipment)) "+ 
      "AND (((:listOfAmenity) is null) or listOfAmenity.id in (:listOfAmenity))") 
    Page<Map<String, Object>> listing(@Param("listOfEquipment") Set<Integer> listOfEquipment,@Param("listOfAmenity") Set<Integer> listOfAmenity) 

上述查询OR工作，但我需要AND

假如我是路过1,2,3 那么结果应该是所有gym谁拥有设备1 and 2 and 3 同为舒适性也

我试图 Finding items with a set containing all elements of a given set with jpql

但它没有帮助荷兰国际集团我监守有多个过滤器

网址是

http://localhost:8080/filter?listOfEquipment=5,3&listOfAmenity=51,13&sort=name 

Answer 1

该查询应该给你Gym.id与假设列表不包含重复项的所有listOfEquipment相匹配。

select g.id as name 
FROM Gym g 
LEFT JOIN g.listOfEquipment listOfEquipment 
WHERE listOfEquipment.id in (:listOfEquipment)) 
GROUP BY g.id 
HAVING count(g.id) = #{#listOfEquipment.size}  

你可以用它在你的主查询为listOfAmenity类似查询的子查询。

select g.name as name 
FROM Gym g 
LEFT JOIN g.listOfEquipment listOfEquipment 
WHERE (((:listOfEquipment) is null) 
    OR g.id in (
    select g.id as name 
    FROM Gym g 
    LEFT JOIN g.listOfEquipment listOfEquipment 
    WHERE listOfEquipment.id in (:listOfEquipment)) 
    GROUP BY g.id 
    HAVING count(g.id) = #{#listOfEquipment.size} 
)) 
AND (((:listOfAmenity) is null) 
    OR g.id in (
    select g.id as name 
    FROM Gym g 
    LEFT JOIN g.listOfAmenity listOfAmenity 
    WHERE listOfAmenity.id in (:listOfAmenity)) 
    GROUP BY g.id 
    HAVING count(g.id) = #{#listOfAmenity.size} 
)) 

Answer 2

没有在最后的，条件 缺少的支架应该是如下

@Query("select g.name as name FROM Gym g " + 
     "LEFT JOIN g.listOfEquipment listOfEquipment " + 
     "WHERE " + 
     "(((:listOfEquipment) is null) or listOfEquipment.id in  (:listOfEquipment)) "+ 
     "AND (((:listOfAmenity) is null) or listOfAmenity.id in (:listOfAmenity))")