Java HtmlUnit用户名和密码登录返回登录页

问题描述:

我想用有效的用户名和密码使用HtmlUnit执行登录。成功登录后,我想在结果页面上执行一些操作。问题是我无法通过登录阶段 - 我一直在同一页面。奇怪的是,我记录了HtmlUnit Scripter Firefox插件的成功登录,然后重播了结果代码 - 同样的问题。有任何想法吗?Java HtmlUnit用户名和密码登录返回登录页

下面是代码:

<pre> 
import com.gargoylesoftware.htmlunit.BrowserVersion; 
import com.gargoylesoftware.htmlunit.FailingHttpStatusCodeException; 
import com.gargoylesoftware.htmlunit.WebClient; 
import com.gargoylesoftware.htmlunit.html.HtmlElement; 
import com.gargoylesoftware.htmlunit.html.HtmlPage; 
import com.gargoylesoftware.htmlunit.html.HtmlPasswordInput; 
import com.gargoylesoftware.htmlunit.html.HtmlTextInput; 

import java.io.IOException; 
import java.net.MalformedURLException; 
<code> 
public class LoginSimulation 
{ 
    public static void main(String args[]) 
    { 
      HtmlPage page = null; 
      String url = "http://www.ravmilim.co.il/naerr.asp"; 

      WebClient webClient = new WebClient(BrowserVersion.FIREFOX_3_6); 
      webClient.setThrowExceptionOnScriptError(false); 

      try 
      { 
       page = webClient.getPage(url); 

       HtmlTextInput userInput = (HtmlTextInput) page.getElementById("txtUser"); 
       userInput.setValueAttribute("[email protected]"); 

       HtmlPasswordInput passwordInput = (HtmlPasswordInput) page.getElementById("txtPass"); 
       passwordInput.setValueAttribute("5750201"); 

       HtmlElement theElement2 = (HtmlElement) page.getElementById("submitButton"); 
       page = theElement2.click(); // the login does not work. Login page is displayed again 

       System.out.println(page.asText()); 
       webClient.closeAllWindows();    
      } 
      catch (FailingHttpStatusCodeException e1) 
      { 
       System.out.println("FailingHttpStatusCodeException thrown:" + e1.getMessage()); 
       e1.printStackTrace(); 
      } 
      catch (MalformedURLException e1) 
      { 
       System.out.println("MalformedURLException thrown:" + e1.getMessage()); 
       e1.printStackTrace(); 
      } 
      catch (IOException e1) 
      { 
       System.out.println("IOException thrown:" + e1.getMessage()); 
       e1.printStackTrace(); 
      } 
      catch(Exception e) 
      { 
       System.out.println("General exception thrown:" + e.getMessage()); 
       e.printStackTrace(); 
      } 
    } 

} 

看起来你的代码就可以了。我已经手动尝试过,有时会记录,有时候不会。问题出在登录操作后出现的弹出窗口中。 你可以看到它从页面上的JavaScript:

if ($("#ErrorDuplicationLogin").text() != '') 
    {  
    $(".PopUpContent").show(); 
    $(".pagePopBackground").show();      

    } 

}); 

所以尝试登录和注销手动,之后启动程序。另外不要忘记使用HtmlUnit注销。谢谢。

+0

你是对的!我注销了其他客户端,并等待先前的htmlunit登录过期,然后我才能够登录!虽然我的问题还没有结束。在下一页中,我试图设置搜索框的值,单击搜索按钮并解析结果。问题是结果显示在另一个框架中,我无法获得其他框架。这里是修改后的代码: – user2045777

+0

System.out.println(page.asText())之后 - 我添加了: – user2045777

+0

HtmlPage framePage =(HtmlPage)nextPage.getFrames()。get(0).getEnclosedPage(); HtmlTextInput searchBox =(HtmlTextInput)framePage.getForms()。get(0).getInputsByName(“searchBox”)。get(0); searchBox.setValueAttribute(“word”); HtmlAnchor anchor = framePage.getHtmlElementById(“sl”); HtmlPage page1 =(HtmlPage)anchor.click(); try { HtmlPage resultsPage =(HtmlPage)page1.getFrameByName(“resault1”)。getEnclosedPage(); (例外e){ e.printStackTrace(); } framePage.getAnchorByHref(“logout.asp”)。click(); – user2045777