使用python的pysftp软件包，试图上传文件时收到OSError

Question

我使用Python 3的paramiko软件包建立sftp连接并上传文件。

我能够通过以下代码成功建立与服务器的连接。

import paramiko 

key_file_test = './path_to_key_file/key_file.pub' 

DOWNLOAD_UAT = { 
    "USERNAME": "xxxxxxxx", 
    "PASSWORD": "xxxxxxxx" 
} 

UAT_FTP_SITE = 'sftp-test.site.com' 

transport = paramiko.Transport((UAT_SFTP_SITE,22)) 
transport.connect(username=DOWNLOAD_UAT['USERNAME'], password=DOWNLOAD_UAT['PASSWORD']) 
transport.add_server_key(key) 
sftp = paramiko.SFTPClient.from_transport(transport) 

print(sftp.listdir()) 
''' ['archiv'] ''' 

sftp.put('test_sftp_upload_file.txt', remotepath='./') 

但是，当我运行上面的最后一行时，我得到以下错误输出。

--------------------------------------------------------------------------- 
OSError         Traceback (most recent call last) 
<ipython-input-69-bec34aeb9958> in <module>() 
----> 1 sftp.put('test_sftp_upload_file.txt', remotepath='./') 

C:\ProgramData\Anaconda3\lib\site-packages\paramiko\sftp_client.py in put(self, localpath, remotepath, callback, confirm) 
    712   file_size = os.stat(localpath).st_size 
    713   with open(localpath, 'rb') as fl: 
--> 714    return self.putfo(fl, remotepath, file_size, callback, confirm) 
    715 
    716  def getfo(self, remotepath, fl, callback=None): 

C:\ProgramData\Anaconda3\lib\site-packages\paramiko\sftp_client.py in putfo(self, fl, remotepath, file_size, callback, confirm) 
    668   .. versionadded:: 1.10 
    669   """ 
--> 670   with self.file(remotepath, 'wb') as fr: 
    671    fr.set_pipelined(True) 
    672    size = self._transfer_with_callback(

C:\ProgramData\Anaconda3\lib\site-packages\paramiko\sftp_client.py in open(self, filename, mode, bufsize) 
    336    imode |= SFTP_FLAG_CREATE | SFTP_FLAG_EXCL 
    337   attrblock = SFTPAttributes() 
--> 338   t, msg = self._request(CMD_OPEN, filename, imode, attrblock) 
    339   if t != CMD_HANDLE: 
    340    raise SFTPError('Expected handle') 

C:\ProgramData\Anaconda3\lib\site-packages\paramiko\sftp_client.py in _request(self, t, *arg) 
    765  def _request(self, t, *arg): 
    766   num = self._async_request(type(None), t, *arg) 
--> 767   return self._read_response(num) 
    768 
    769  def _async_request(self, fileobj, t, *arg): 

C:\ProgramData\Anaconda3\lib\site-packages\paramiko\sftp_client.py in _read_response(self, waitfor) 
    817     # synchronous 
    818     if t == CMD_STATUS: 
--> 819      self._convert_status(msg) 
    820     return t, msg 
    821 

C:\ProgramData\Anaconda3\lib\site-packages\paramiko\sftp_client.py in _convert_status(self, msg) 
    850    raise IOError(errno.EACCES, text) 
    851   else: 
--> 852    raise IOError(text) 
    853 
    854  def _adjust_cwd(self, path): 

OSError: Bad message 

我在这里请遵照docs http://docs.paramiko.org/en/2.2/api/sftp.html来构建我的代码，以及用于包装的paramiko。

Answer 1

根据文档，您应该指定完整的远程文件路径。

:param str remotepath: the destination path on the SFTP server. Note 
     that the filename should be included. Only specifying a directory 
     may result in an error.