PHP文件路径命名问题
问题描述:
我尝试创建一个脚本来上传多张照片,重命名照片并添加数据库条目。数据库文件名条目是正确的,但图像上传文件名是复合JPG名称。PHP文件路径命名问题
即。数据库条目正确命名文件:photo_1,photo_2,photo_3
将正在上传文件命名错误:photo_1.jpg,photo_1.jpgphoto_2.jpg,photo_1.jpgphoto_2.jpgphoto_3.jpg
不知道如何解决这是因为我的数据库条目是正确的。
<?php
if (isset($_POST['submit'])) {
$j = 0; //Variable for indexing uploaded image
$image_post_id = $_POST["image_post_id"];
$target_path = "uploads/"; //Declaring Path for uploaded images
for ($i = 0; $i < count($_FILES['file']['name']); $i++) {//loop to get individual element from the array
$validextensions = array("jpeg", "jpg", "png", "JPG", "PNG", "JPEG"); //Extensions which are allowed
$ext = explode('.', basename($_FILES['file']['name'][$i]));//explode file name from dot(.)
$file_extension = end($ext); //store extensions in the variable
//MYSQL Handling
mysql_query("INSERT INTO post_images(`image_filename`, `image_post_id`) VALUES('0', '".addslashes($image_post_id)."')");
$new_id = mysql_insert_id();
$target_path = $target_path . "post_". $new_id . "." . strtolower($ext[count($ext) - 1]);//set the target path with a new name of image
mysql_query("UPDATE post_images SET image_filename='post_".addslashes($new_id).".".strtolower($ext[count($ext) - 1])."' WHERE image_id='".addslashes($new_id)."'");
$j = $j + 1;//increment the number of uploaded images according to the files in array
if (($_FILES["file"]["size"][$i] < 1000000) //Approx. 100kb files can be uploaded.
&& in_array($file_extension, $validextensions)) {
if (move_uploaded_file($_FILES['file']['tmp_name'][$i], $target_path)) {//if file moved to uploads folder
echo $j. ').<span id="noerror">Image uploaded successfully!.</span><br/><br/>';
} else {//if file was not moved.
echo $j. ').<span id="error">please try again!.</span><br/><br/>';
}
} else {//if file size and file type was incorrect.
echo $j. ').<span id="error">***Invalid file Size or Type***</span><br/><br/>';
}
}
}
?>
答
你的问题是这条线在你的for循环:
$target_path = $target_path . "post_". $new_id . "." . strtolower($ext[count($ext) - 1]);
此代码实际上是说“追加新的文件名到前值”,这显然不是你想要的。
要解决,只是删除$target_path
上=
的权利:
$target_path = "post_". $new_id . "." . strtolower($ext[count($ext) - 1]);
停止你正在做什么,NOW。您正在使用已弃用的,未维护且不安全的数据库API。 PDO等替代品已有十多年的历史。请参阅http://*.com/questions/12859942/why-shouldnt-i-use-mysql-functions-in-php – miken32
为了帮助人们回答您的问题,我可以提出两点建议:1-格式化您发布的代码更具可读性。 2-告诉你期望的结果(应该得到的最终名称,即使我可以从你的代码中得到它,总是很明确的)。 –