减去当前日期和时间5分钟javascript
从当前日期减少时间,我有问题。我的代码如下所示:减去当前日期和时间5分钟javascript
var d = new Date(),
year = d.getUTCFullYear(),
month = ('0'+(d.getUTCMonth()+1)).slice(-2),
day = ('0'+d.getUTCDate()).slice(-2),
hour = ('0'+d.getUTCHours()).slice(-2),
minute = ('0'+d.getUTCMinutes()).slice(-2),
second = ('0'+d.getUTCSeconds()).slice(-2);
var startDate = year+'/'+month+'/'+day+'-'+hour+':'+minute+':'+second;
console.log(startDate);
获取的毫秒日期变量,subs 5分钟,并从中创建一个新的日期对象:
var d = new Date()
// d = Mon Feb 29 2016 08:00:09 GMT+0100 (W. Europe Standard Time)
var milliseconds = Date.parse(d)
// 1456729209000
milliseconds = milliseconds - (5 * 60 * 1000)
// - 5 minutes
d = new Date(milliseconds)
// d = Mon Feb 29 2016 07:55:04 GMT+0100 (W. Europe Standard Time)
谢谢.... @ Gerald Schneider – Karan
您可以通过
minute = ('0'+d.getUTCMinutes()).slice(-2)-5
var d = new Date(),
year = d.getUTCFullYear(),
month = ('0'+(d.getUTCMonth()+1)).slice(-2),
day = ('0'+d.getUTCDate()).slice(-2),
hour = ('0'+d.getUTCHours()).slice(-2),
minute = ('0'+d.getUTCMinutes()).slice(-2),
second = ('0'+d.getUTCSeconds()).slice(-2);
if (minute>=5)
minute = minute-5;
else {
minute = (parseInt(minute) + 60) - 5;
hour = hour - 1;
}
var startDate = year+'/'+month+'/'+day+'-'+hour+':'+minute+':'+second;
alert(startDate);
为只需要3个命令的任务添加14kb的代码似乎有点过分。 –
只是一个建议。适合复杂的日期驱动应用程序。 –
你可以使用这样的
var original = new Date();
var subtract5min = new Date();
alert("before : " + original);
subtract5min.setTime(original.getTime() - 5*60*1000);
alert("after : " + subtract5min);
这也可能导致负面分钟。 –
谢谢,更新了我的答案 – C2486
最新问题? –
问题是这是当前时间,我想从这个时间减去5分钟 – Karan
minute =('0'+ d.getUTCMinutes())。slice(-2) - (5), –