试图JSON数据转换成JSON数组Android Studio中

问题描述：

你好我尝试一些JSON数据转换成一个数组，我不这样说之前，但没有对象试图JSON数据转换成JSON数组Android Studio中

http://earthquake.usgs.gov/earthquakes/feed/v1.0/summary/1.0_day.geojson

下面是代码该获取数据，并改掉其转换

public JSONArray getQaukes() 
{ 


    String url = "http://earthquake.usgs.gov/earthquakes/feed/v1.0/summary/1.0_day.geojson"; 
    // Get HttpResponse Object from url. 
    // Get HttpEntity from Http Response Object 

    HttpEntity httpEntity = null; 

    try 
    { 

     DefaultHttpClient httpClient = new DefaultHttpClient(); // Default HttpClient 
     HttpGet httpGet = new HttpGet(url); 

     HttpResponse httpResponse = httpClient.execute(httpGet); 

     httpEntity = httpResponse.getEntity(); 



    } catch (ClientProtocolException e) { 

     // Signals error in http protocol 
     e.printStackTrace(); 



    } catch (IOException e) { 
     e.printStackTrace(); 
    } 


    // Convert HttpEntity into JSON Array 
    JSONArray jsonArray = null; 

    if (httpEntity != null) { 
     try { 
      String entityResponse = EntityUtils.toString(httpEntity); 

      Log.d("Entity Response : ", entityResponse); 

      jsonArray = new JSONArray(entityResponse); 

     } catch (JSONException e) { 
      e.printStackTrace(); 
     } catch (IOException e) { 
      e.printStackTrace(); 
     } 
    } 

    return jsonArray; 


}

这就是我得到 http://pastebin.com/HVnx3gsq

任何人都知道我可以如何找到正确的方法来做到这一点？感谢

答

编辑：举个例子，如果你要提取“功能”阵列，那么你应该那样做：

//First of all - create JSON Object which you are going to parse (deserialize JSON string) 
JSONObject jsonObj = new JSONObject(entityResponse); 
// Extract JSON array from Object 
JSONArray jsonArray = jsonObj.getJSONArray("features");

你的JSON字符串中有许多不同的元素，这就是为什么你需要创建JSON对象，然后从中提取数组等等。直到最后一个标记。

"type":"FeatureCollection", 
"metadata":{ 
    "generated":1452461493000, 
    "url":"http://earthquake.usgs.gov/earthquakes/feed/v1.0/summary/1.0_day.geojson", 
    "title":"USGS Magnitude 1.0+ Earthquakes, Past Day", 
    "status":200, 
    "api":"1.1.0", 
    "count":128 
}, 
"features":[ 
    { 
    "type":"Feature", 
    "properties":{ 
     "mag":2.07, 
     "place":"28km S of Gardnerville Ranchos, Nevada", 
     "time":1452460963440, 
     "updated":1452461071893, 
     "tz":-480, 
     "url":"http://earthquake.usgs.gov/earthquakes/eventpage/nc72578341", 
     "detail":"http://earthquake.usgs.gov/earthquakes/feed/v1.0/detail/nc72578341.geojson", 
     "felt":null, 
     "cdi":null, 
     "mmi":null, 
     "alert":null, 
     "status":"automatic", 
     "tsunami":0, 
     "sig":66, 
     "net":"nc", 
     "code":"72578341", 
     "ids":",nn00526227,nc72578341,", 
     "sources":",nn,nc,", 
     "types":",general-link,general-link,geoserve,nearby-cities,origin,phase-data,", 
     "nst":8, 
     "dmin":0.06765, 
     "rms":0.11, 
     "gap":197, 
     "magType":"md", 
     "type":"earthquake", 
     "title":"M 2.1 - 28km S of Gardnerville Ranchos, Nevada" 
    }, 
    "geometry":{ 
     "type":"Point", 
     "coordinates":[ 
      -119.751503, 
      38.6351662, 
      -1.8 
     ] 
    }, 
    "id":"nc72578341" 
    }, 
    { 
    "type":"Feature", 
    "properties":{ 
     "mag":2.3,

在你上面的提取物具有： “类型” - JSON值， “元数据” - JSON对象， “特征” - JSON阵列等。

我建议你寻找到JSON的语法，所以那么你就能理解如何分析数据：http://www.w3schools.com/json/json_syntax.asp

感谢您对这样的快速回复，我会看看的语法和尝试将对象转换为数组。：D – ThatFellaNick

@ThatFellaNick查看答案开头的更新。 –

感谢您的帮助，我能够获得我需要的所有数据！：D – ThatFellaNick

答

结果是JSONObject不JSONArray。

而不是JSONArray jsonArray = new JSONArray(entityResponse);

你应该有JSONObject jObj = new JSONObject(entityResponse);

试图JSON数据转换成JSON数组Android Studio中

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