由DATEPART()组错误/错误
我遇到了由DATEPART()子句组出现的问题。我的代码是由DATEPART()组错误/错误
SELECT con.Name, con.contractID, Sum(cplanit.Cost) as costs, DATENAME(month,month(cplanit.PaymentDate)) as month, year(cplanit.PaymentDate) as year
FROM ContractTable con
INNER JOIN [a lot of tables] ON [joins proofed and working fine]
Group By con.Name, con.contractID, DATEPART(month,cplanit.PaymentDate), DATEPART(year,cplanit.PaymentDate)
我得到这个:
Adobe CLP Agreement - Initial purchase C00012121 18.7500 January 2011
Adobe CLP Agreement - Initial purchase C00012121 18.7500 January 2010
Adobe CLP Agreement - Initial purchase C00012121 18.7500 January 2011
Adobe CLP Agreement - Initial purchase C00012121 18.7500 January 2010
Adobe CLP Agreement - Initial purchase C00012121 18.7500 January 2011
相同的条目。费用按确切的付款日期进行分组,而不是每月和每年 - 这是我需要做的。如果我在SELECT子句中删除日期名称和年份,或者仅按月或年分组,则会出现此问题。对DATEPART(),month()或year()进行分组工作正常。也许这是我错过的简单东西?有时我只是盲目。
在SQL Server Management Studio中/ SQL Server 2012的
您在GROUP不privide通过在SELECT子句提供子句领域遇到。请尝试以下操作:
SELECT con.Name, con.contractID, Sum(cplanit.Cost) as costs, DATENAME(month,month(cplanit.PaymentDate)) as month, year(cplanit.PaymentDate) as year
FROM ContractTable con
INNER JOIN [a lot of tables] ON [joins proofed and working fine]
GROUP BY con.Name, con.contractID, DATENAME(month,month(cplanit.PaymentDate)), year(cplanit.PaymentDate)
反正它工作在所有情况下:
CREATE TABLE #Tempas
(
Name NVARCHAR(80),
contractID NVARCHAR(20),
Data DATETIME2
)
INSERT INTO #Tempas VALUES('Adobe CLP Agreement - Initial purchase' ,'1','20010101 10:10:10')
INSERT INTO #Tempas VALUES('Adobe CLP Agreement - Initial purchase' ,'1','20010101 10:10:10')
INSERT INTO #Tempas VALUES('Adobe CLP Agreement - Initial purchase' ,'1','20010101 10:10:10')
INSERT INTO #Tempas VALUES('Adobe CLP Agreement - Initial purchase' ,'1','20010101 10:10:10')
INSERT INTO #Tempas VALUES('Adobe CLP Agreement - Initial purchase' ,'1','20020101 10:10:10')
INSERT INTO #Tempas VALUES('Adobe CLP Agreement - Initial purchase' ,'1','20020101 10:10:10')
INSERT INTO #Tempas VALUES('Adobe CLP Agreement - Initial purchase' ,'1','20020101 10:10:10')
INSERT INTO #Tempas VALUES('Adobe CLP Agreement - Initial purchase' ,'1','20020101 10:10:10')
SELECT Name, contractID, DATENAME(month,month(data)) AS Month, year(data) AS year
FROM #Tempas
GROUP BY Name, contractID, DATEPART(month,data), DATEPART(year,data)
DROP TABLE #tempas
OUTPUT:
Name contractID Month year
Adobe CLP Agreement - Initial purchase 1 January 2001
Adobe CLP Agreement - Initial purchase 1 January 2002
在相同的价值观和下面的查询:
SELECT Name, contractID, DATENAME(month,month(data)) AS Month, year(data) AS year
FROM #Tempas
GROUP BY Name, contractID, DATENAME(month,month(data)), year(data)
输出相同:
Name contractID Month year
Adobe CLP Agreement - Initial purchase 1 January 2001
Adobe CLP Agreement - Initial purchase 1 January 2002
非常感谢你 –
的代码似乎很好地工作,因为它是,即使by子句当前组。问题是否可以在查询的另一部分?
declare @ContractTable table (
Name nvarchar(20),
ContractId int,
Cost Decimal,
PaymentDate DateTime)
insert into @ContractTable values ('Name', 1, 100, N'20150101')
insert into @ContractTable values ('Name', 2, 100, N'20150101')
insert into @ContractTable values ('Name', 1, 100, N'20150102')
insert into @ContractTable values ('Name', 1, 100, N'20150102')
insert into @ContractTable values ('Name', 2, 100, N'20150104')
insert into @ContractTable values ('Name', 2, 100, N'20150104')
insert into @ContractTable values ('Name', 2, 100, N'20150105')
insert into @ContractTable values ('Name', 2, 100, N'20150105')
insert into @ContractTable values ('Name', 2, 100, N'20150105')
insert into @ContractTable values ('Name', 2, 100, N'20150105')
SELECT
Name
,contractID
,Sum(Cost) as costs
,DATENAME(month,month(PaymentDate)) as [month]
,year(PaymentDate) as [year]
FROM
@ContractTable
Group By
Name
,contractID
,DATEPART(month,PaymentDate)
,DATEPART(year, PaymentDate)
谢谢,你是对的(比较我的评论):) –
此外:为什么group by子句与SELECT字段不同?您是否尝试过:GROUP BY con.Name,con.contractID,DATENAME(month,month(cplanit.PaymentDate)),year(cplanit.PaymentDate) – ericpap
“成本按确切的PaymentDate分组”我必须在这里纠正自己,每个月只有一个PaymentDate,与我的想法相反。对不起,我的文章,我得到了解决方案:连接产生了多行。因此,“独特”解决了这个问题。无论如何,非常感谢你,*证明对我来说非常有用多次:) –
@TedOckham。 。 。考虑删除问题。 –