PHP:如何将一个嵌套数组变成一维数组?
问题描述:
这是一个嵌套的数组,我从我的数据库了,PHP:如何将一个嵌套数组变成一维数组?
Array
(
[0] => Array
(
[Field] => blc_id
[Type] => int(10) unsigned
[Null] => NO
[Key] => PRI
[Default] =>
[Extra] => auto_increment
)
[1] => Array
(
[Field] => blc_email
[Type] => varchar(255)
[Null] => YES
[Key] =>
[Default] =>
[Extra] =>
)
[2] => Array
(
[Field] => cat_id
[Type] => varchar(255)
[Null] => YES
[Key] =>
[Default] =>
[Extra] =>
)
[3] => Array
(
[Field] => blc_created
[Type] => timestamp
[Null] => NO
[Key] =>
[Default] => 0000-00-00 00:00:00
[Extra] =>
)
[4] => Array
(
[Field] => blc_updated
[Type] => timestamp
[Null] => NO
[Key] =>
[Default] => CURRENT_TIMESTAMP
[Extra] => on update CURRENT_TIMESTAMP
)
)
如何使用foreach循环得到下面的结果,
Array
(
[0] => blc_id
[1] => blc_email
[2] => cat_id
[3] => blc_created
[4] => blc_updated
)
这是到目前为止我的代码,但当然它不正确返回结果,
foreach($items as $outer_key => $array)
{
foreach($array as $inner_key => $value)
{
$field_name[] = $value;
}
}
谢谢。
答
我想你可以使用
foreach($items as $outer_key => $array)
{
$field_name[] = $array['Field'];
}
答
当你只需要从每一个子阵列中的第一项:
$field_names = array_map("current", $outer_key);
答
$fields = array();
foreach($input_array as $value)
$fields[] = $value['Field'];
print_r($fields);
答
array_map(create_function('$a','return $a["Field"];'),$a)
为什么你不改变你的查询,而不是处理结果与PHP? – Elwhis 2011-03-25 15:03:50
我不知道如何改变我的查询......这里是 - 从'root_blocks'显示列。谢谢。 – laukok 2011-03-25 15:16:07