从另一个对象分配一个对象属性

Question

如何使用变量作为新属性为对象提供新属性？

下给我所需要的属性对象：

switch ($property['property_type']): 
    case 'Residential': 
     $property = $this->property 
         ->join('residential', 'property.id', '=','residential.property_id') 
         ->join('vetting', 'property.id', '=', 'vetting.property_id') 
         ->where('property.id', $id) 
         ->first(); 

     $property['id'] = $id; 
     break; 
    default: 
     return Redirect::route('property.index'); 
     break; 
endswitch; 

下面给我的属性和值的列表：

$numeric_features = App::make('AttributesController')->getAttributesByType(2); 

这里的问题是，如何动态地添加各$numeric_features属性对象？

foreach ($numeric_features as $numeric_feature) { 
    ***$this->property->{{$numeric_feature->name}}***=$numeric_feature->value; 
} 

Answer 1

看看http://php.net/manual/en/function.get-object-vars.php

$property_names = array_keys(get_object_vars($numeric_features)); 

foreach ($property_names as $property_name) { 
    $property->{$property_name} = $numeric_features->{$property_name}; 
} 

，并检查该EVAL结果，它增加了一个对象的属性到另一个对象： https://eval.in/517743

$numeric_features = new StdClass; 
$numeric_features->a = 11; 
$numeric_features->b = 12; 

$property = new StdClass; 
$property->c = 13; 

$property_names = array_keys(get_object_vars($numeric_features)); 

foreach ($property_names as $property_name) { 
    $property->{$property_name} = $numeric_features->{$property_name}; 
} 
var_dump($property); 

结果：

object(stdClass)#2 (3) { 
    ["c"]=> 
    int(13) 
    ["a"]=> 
    int(11) 
    ["b"]=> 
    int(12) 
}