获取致命错误

Question

我收到此错误：

Fatal error: Unsupported operand types in C:\xampp\htdocs\process.php on line 59("$total = calculate_size_cost() + calculate_topping_cost() + calculate_delivery_cost();")

<?php 
    $name = $_GET['name']; 
    $phone = $_GET['phone']; 
    $address = $_GET['address']; 
    $size = $_GET['size']; 
    $topping = $_GET['topping']; 
    $delivery = $_GET['deliverytype']; 
    $comment=$_GET['comments']; 

    mysql_connect ("localhost", "root", "") or die ('Error: ' . mysql_error()); 
    mysql_select_db ("pizza"); 
    $query ="INSERT INTO orders (name, phone, address, size, topping, delivery, comments) VALUES ('".$name."', '".$phone."', '".$address."','".$size."','".$topping."','".$delivery."','".$comment."')"; 



    $total = 0; 
    $total = calculate_size_cost() + calculate_topping_cost() + calculate_delivery_cost(); 

    echo "Dear $name your {$_GET["size"]} pizza has been ordered."; 
    echo "Your Total is $ $total"; 
    echo "\n\n\nYour Toppings: {$_GET["topping"]}"; 
    echo "\nYour Comments: {$_GET["comments"]}"; 
    echo "Your Delivery Type:{$_GET["deliverytype"]}"; 

    function calculate_size_cost() { 
     $size = 0; 
     if ($_GET['size'] == "Small"){ 
      $size+=5; 

     } 
     else if ($_GET['size'] == "Medium"){ 
      $size+=10; 

     } 
     else if ($_GET['size'] == "Large"){ 
      $size+=15; 
     } 
     return $size; 


    } 

    function calculate_topping_cost() { 
     $topping = 1; 
     return $_GET['topping']; 
    } 

    function calculate_delivery_cost() { 
     $delivery_cost = 0; 
     if ($_GET['deliverytype'] == "delivery") { 
      $delivery_cost += 5; 
     } 
     return $delivery_cost; 
    } 
    ?> 

Answer 1

尝试类型转换（u可以使用（浮动）或任何ü需要，使用IM（INT）

$size =(int) $_GET['size']; 
$topping =(int)$_GET['topping']; 
$delivery = (int)$_GET['deliverytype']; 

也做同样的每个功能的返回值，如

return (int)$size;等等......关于

@Ankur一个建议：改变插入的语法（我喜欢这个）

$query =" INSERT INTO orders SET 
       name='".$name."', 
       phone='".$phone."', 
       address='".$address."', 
       size='".$size."', 
       topping='".$topping."', 
       delivery='".$delivery."', 
       comments='".$comment."')"; 

然后写

$done=mysql_query($query); 
echo $done; 

Answer 2

您返回GET数组，而不是你的结果。

function calculate_topping_cost() { 
    $topping = 1; 
    return $_GET['topping']; 
} 

试试这个：

function calculate_topping_cost() { 
    $topping = 1; 
    return $topping; 
} 

Answer 3

$_GET["topping"]可能包含的东西是不是数字。 你可能会迫使它转换：

function calculate_topping_cost() { 
     $topping = 1; 
     return (int) $_GET['topping']; 
    } 

这将返回0如果topping不是一个数字。

但是，您可能希望明确地捕获该条件或修复代码 - 该函数没有多大意义，这可能只是一个错误。