格式化字典打印输出
问题描述:
我有一个名为d
的字典,它有几个存储在其中的列表。如果我打印的字典我得到这个难读输出:格式化字典打印输出
{'Patch(0,8)': [28, 56, 75], 'Patch(0,6)': [1, 11, 17, 19, 20, 23, 28, 30, 44, 45, 49, 56, 60, 63, 75, 81, 91, 99],
'Patch(4,0)': [2, 5, 6, 8, 19, 22, 23, 27, 31, 34, 35, 36, 41, 45, 51, 52, 53, 55, 56, 59, 60, 61, 62, 64, 66, 67, 68, 70, 73, 75, 76, 77, 79, 85, 87, 91, 94, 96],
'Patch(4,6)': [19, 23, 45, 56, 60, 75, 91], 'Patch(0,0)': [0, 1, 2, 3, 4, 5, 6, 7, 8, 9,
10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 22, 23, 24, 25, 26, 27, 28, 29, 30, 31, 32, 33, 34, 35, 36, 37, 38, 39, 40, 41, 42, 43, 44, 45, 46, 47, 48, 49, 50, 51, 52, 53, 54, 55, 56,
57, 58, 59, 60, 61, 62, 63, 64, 65, 66, 67, 68, 69, 70, 71, 72, 73, 74, 75, 76, 77, 78, 79, 80, 81, 82, 83, 84, 85, 86, 87, 88, 89, 90, 91, 92, 93, 94, 95, 96, 97, 98, 99], 'Patch(8,0)': [2, 22, 23, 27, 34, 52
, 55, 60, 85], 'Patch(0,2)': [0, 1, 2, 3, 4, 6, 7, 10, 11, 13, 15, 16, 17, 18, 19, 20, 22, 23, 25, 26, 28, 29, 30, 32, 34, 36, 37, 38, 40, 43, 44, 45, 46, 47,
49, 50, 51, 52, 53, 54, 56, 58, 59, 60, 61, 62, 63, 64, 66, 70, 71, 74, 75, 76, 77, 78, 80, 81, 83, 85, 90, 91, 92, 93, 94, 96, 98, 99], 'Patch(2,8)': [28, 56, 75], 'Patch(4,8)': [56, 75]}
我只是想在一个新行打印每个Patch
和相应的数据:
{'Patch(0,8)': [28, 56, 75],
'Patch(0,6)': [1, 11, 17, 19, 20, 23, 28, 30, 44, 45, 49, 56, 60, 63, 75, 81, 91, 99],
我看到的建议后试图pprint
this answer :
pprint.pprint(d, width=1)
我得到这个:
{'Patch(0,8)': [28,
56,
75], and so on
我在这里错过了什么?
答
只是通过在宽度是大到足以容纳在dict
每个值:
>>> pprint.pprint(d, width=1000)
{'Patch(0,0)': [0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 22, 23, 24, 25, 26, 27, 28, 29, 30, 31, 32, 33, 34, 35, 36, 37, 38, 39, 40, 41, 42, 43, 44, 45, 46, 47, 48, 49, 50, 51, 52, 53, 54, 55, 56, 57, 58, 59, 60, 61, 62, 63, 64, 65, 66, 67, 68, 69, 70, 71, 72, 73, 74, 75, 76, 77, 78, 79, 80, 81, 82, 83, 84, 85, 86, 87, 88, 89, 90, 91, 92, 93, 94, 95, 96, 97, 98, 99],
'Patch(0,2)': [0, 1, 2, 3, 4, 6, 7, 10, 11, 13, 15, 16, 17, 18, 19, 20, 22, 23, 25, 26, 28, 29, 30, 32, 34, 36, 37, 38, 40, 43, 44, 45, 46, 47, 49, 50, 51, 52, 53, 54, 56, 58, 59, 60, 61, 62, 63, 64, 66, 70, 71, 74, 75, 76, 77, 78, 80, 81, 83, 85, 90, 91, 92, 93, 94, 96, 98, 99],
'Patch(0,6)': [1, 11, 17, 19, 20, 23, 28, 30, 44, 45, 49, 56, 60, 63, 75, 81, 91, 99],
'Patch(0,8)': [28, 56, 75],
'Patch(2,8)': [28, 56, 75],
'Patch(4,0)': [2, 5, 6, 8, 19, 22, 23, 27, 31, 34, 35, 36, 41, 45, 51, 52, 53, 55, 56, 59, 60, 61, 62, 64, 66, 67, 68, 70, 73, 75, 76, 77, 79, 85, 87, 91, 94, 96],
'Patch(4,6)': [19, 23, 45, 56, 60, 75, 91],
'Patch(4,8)': [56, 75],
'Patch(8,0)': [2, 22, 23, 27, 34, 52, 55, 60, 85]}
答
你可以把它变成一个简单的循环来打印它。看官方文档dict.iteritems
。
for key, value in d.iteritems():
print key + " - " + str(value)
答
我通常会打印作为JSON的字典给它结构和格式我可以很容易地阅读。
import json
json.dumps(dict(a=1, b=2), indent=2)
+0
但是,这并不是OP想要的,它将列表项放在不同的行上。使用JSON来显示字典_can_方便,但它有各种限制:非字符串键被转换为字符串; 'None','True'和'False'被转换为JSON等价物。 –
FWIW,在Python 3'dict.iteritems'不存在。相反,'dict.items'现在返回一个迭代器,所以你可以在必须在两个版本上运行的代码中使用'dict.items'(当然在Python 2中它将返回一个列表而不是迭代器,所以它'可能会使用更多的RAM)。 –