使用共享URL的图像参数显示facebook共享图像的问题
问题描述:
我使用的是Facebook共享url,但无法显示url的图像参数,任何人都可以告诉我哪里可能会出错?使用共享URL的图像参数显示facebook共享图像的问题
HTML
<a title="Share this on Facebook"
href="http://www.facebook.com/sharer.php?
s=100
&p[url]='http://www.test.com'
&p[images][0]='http://www.meandmrsjoneshotel.com/wp-content/themes/child-theme/img/fb-thumbs/home.png'
&p[title]='This is the title'
&p[summary]='This is the share description'"
target="_blank" class="fb ir">
Share this page on Facebook
</a>
JS小提琴http://jsfiddle.net/pUMZb/
感谢
答
尝试删除撇号。你的代码应该是这样的
<a title="Share this on Facebook"
href="http://www.facebook.com/sharer.php?
s=100
&p[url]='http://www.test.com'
&p[images][0]=http://www.meandmrsjoneshotel.com/wp-content/themes/child-theme/img/fb-thumbs/home.png
&p[title]='This is the title'
&p[summary]='This is the share description'"
target="_blank" class="fb ir">
Share this page on Facebook
</a>
请使用Like按钮插件(https://developers.facebook.com/docs/reference/plugins/like/)共享有道,据我所知sharer.php有已退休。 – deesarus