如何访问哈希

Question

我有这个工作与复杂的阵列：

[ 
    ["app1", {"name"=>"name1", "path"=>"xyz.com/"}], 
    ["app2", {"name"=>"name2", "path"=>"xyz.com/"}], 
    ["app3", {"name"=>"name3", "path"=>"xyz.com/"}], 
    # etc. 
] 

我希望能够访问每个名称和路径，所以我尝试：

apps.each do |key, value| 
    value.each do |key, value| 
    puts value 
    end 
end 

但这返回枚举。任何想法我怎么能做到这一点？

Answer 1

apps = [["app1", {"name"=>"name1", "path"=>"https://xyz.com/"}], ["app2", {"name"=>"name2", "path"=>"https:/xyz.com/"}], ["app3", {"name"=>"name3", "path"=>"https://xyz.com/"}]] 
apps.flatten.each do |t| 
    next unless t.class == Hash 
    next unless t.key?("name") 
    next unless t.key?("path") 
    puts t.inspect # now t is a hash that has both "name" and "path" keys - do what you want 
end 

当你有不同的元素不同的结构本可以处理得有些更复杂的情况。

Answer 2

我想你的第一个每个循环只遍历数组，所以这将是：

apps.each do |app| 
    app.each do |key, value| 
    puts key # would be app1 in the first array 
    puts value["name"] 
    puts value["path"] 
    end 
end 

Answer 3

ar = [ 
    ["app1", {"name"=>"name1", "path"=>"xyz.com/"}], 
    ["app2", {"name"=>"name2", "path"=>"xyz.com/"}], 
    ["app3", {"name"=>"name3", "path"=>"xyz.com/"}] 

] 
#Get a specific app: 
p ar.assoc("app2").last["name"] 
#Get all names and paths 
ar.each{|app| name, path = app.last["name"], app.last["path"]}