R - 鼠标 - 添加一列,用于将列与估算值相加
问题描述:
我有一个缺失数据的数据库。我需要推算数据(我使用鼠标),然后基于原始列(使用推算数据)创建新列。正是这些新的列需要我进行统计分析。R - 鼠标 - 添加一列,用于将列与估算值相加
具体来说,我的参与者用7点Likert量表填写了几个问卷。有些人没有回答所有问题。我需要估算值,然后对这些值进行求和,并根据这个总和获得这个新值,以便进行统计分析,根据这个总和将参与者分成“轻度,中度,高度”并将其用于统计分析。
我有什么依据我想这个答案计算器做: Perform operation on each imputed dataset in R's MICE
这里是我的代码(使用R):
# Create a sample bdd
bdd=data.frame(
gender=c("M","F","M", "M", "M", "F"),
choice=c(1,2,NA,1,1,1),
gardes=c(0,0,0,5,7,NA),
EE1=c(3,4,1,NA,3,0),
EE2=c(2,5,1,3,3,0),
EE3=c(3,NA,1,5,3,0),
EE4=c(3,6,1,2,3,0),
EE5=c(1,4,1,2,3,5),
EE6=c(3,1,1,3,3,4),
EE7=c(5,0,1,5,3,5),
EE8=c(2,6,1,1,3,3),
EE9=c(3,4,1,6,3,4)
)
# Create the additional variable - this will have missing values
bdd$EE <- bdd$EE1+bdd$EE2+bdd$EE3+bdd$EE4+bdd$EE5+bdd$EE6+bdd$EE7+bdd$EE8+bdd$EE9
# create ini to get access to meth and pred
ini <- mice(bdd, max = 0, print = FALSE)
# Change the method of imputation for EE, so that it always equals bdd$EE1+...+bdd$EE9
meth1 <- ini$meth
meth1["EE"] <- "~I(bdd$EE1+bdd$EE2+bdd$EE3+bdd$EE4+bdd$EE5+bdd$EE6+bdd$EE7+bdd$EE8+bdd$EE9)"
pred1 <- ini$pred
# change the predictor matrix so only bdd$EE1-9 predicts EE (necessary?)
pred1[ "EE", ] <- 0
pred1[ "EE", c("EE1", "EE2", "EE3", "EE4", "EE5", "EE6", "EE7", "EE8", "EE9")] <- 1
# change the predictor matrix so that EE isnt used to predict
pred1[ , "EE" ] <- 0
# Imputations
imput <- mice(bdd, seed=1, pred = pred1, meth = meth1, m=1, print = FALSE)
请注意,这是行不通的。任何其他方式来优雅地做到这一点?任何和所有意见的TIA!
编辑补充:这是错误消息我收到的时候我尝试运行这段代码:
Warning messages:
1: In `[<-.data.frame`(`*tmp*`, , i, value = list(`1` = c(20L, 14L, :
replacement element 1 has 456 rows to replace 2 rows
2: In `[<-.data.frame`(`*tmp*`, , i, value = list(`1` = c(20L, 14L, :
replacement element 1 has 456 rows to replace 2 rows
3: In `[<-.data.frame`(`*tmp*`, , i, value = list(`1` = c(20L, 14L, :
replacement element 1 has 456 rows to replace 2 rows
4: In `[<-.data.frame`(`*tmp*`, , i, value = list(`1` = c(20L, 14L, :
replacement element 1 has 456 rows to replace 2 rows
5: In `[<-.data.frame`(`*tmp*`, , i, value = list(`1` = c(20L, 14L, :
replacement element 1 has 456 rows to replace 2 rows
下面是我对这个问题产生的BDD:
gender choice gardes EE1 EE2 E3 EE4 EE5 EE6 E7 EE8 EE9
1 M 1 0 3 2 3 3 1 3 5 2 3
2 F 2 0 4 5 NA 6 4 1 0 6 4
3 M NA 0 1 1 1 1 1 1 1 1 1
4 M 1 5 NA 3 5 2 2 3 5 1 6
5 M 1 7 3 3 3 3 3 3 3 3 3
6 F 1 NA 0 0 0 0 5 4 5 3 4
答
下面的代码没有错误,在user20650指出的更正之后!
# Create a sample bdd
bdd=data.frame(
gender=c("M","F","M", "M", "M", "F"),
choice=c(1,2,NA,1,1,1),
gardes=c(0,0,0,5,7,NA),
EE1=c(3,4,1,NA,3,0),
EE2=c(2,5,1,3,3,0),
EE3=c(3,NA,1,5,3,0),
EE4=c(3,6,1,2,3,0),
EE5=c(1,4,1,2,3,5),
EE6=c(3,1,1,3,3,4),
EE7=c(5,0,1,5,3,5),
EE8=c(2,6,1,1,3,3),
EE9=c(3,4,1,6,3,4)
)
# Create the additional variable - this will have missing values
bdd$EE <- bdd$EE1+bdd$EE2+bdd$EE3+bdd$EE4+bdd$EE5+bdd$EE6+bdd$EE7+bdd$EE8+bdd$EE9
# create ini to get access to meth and pred
ini <- mice(bdd, max = 0, print = FALSE)
# Change the method of imputation for EE, so that it always equals bdd$EE1+...+bdd$EE9
meth1 <- ini$meth
meth1["EE"] <- "~I(EE1+EE2+EE3+EE4+EE5+EE6+EE7+EE8+EE9)"
pred1 <- ini$pred
# change the predictor matrix so only bdd$EE1-9 predicts EE (necessary?)
pred1[ "EE", ] <- 0
pred1[ "EE", c("EE1", "EE2", "EE3", "EE4", "EE5", "EE6", "EE7", "EE8", "EE9")] <- 1
# change the predictor matrix so that EE isnt used to predict
pred1[ , "EE" ] <- 0
# Imputations
imput <- mice(bdd, seed=1, pred = pred1, meth = meth1, m=1, print = FALSE)
+0
请注意,我不是100%确定改变预测矩阵的代码是正确的,如果你想使用这个代码,请首先仔细检查,谢谢! – Zephyr
嗨,欢迎来到SO,你会补充一点你的缺失值的例子数据?也许只有几行'bdd'?如果没有测试数据,很难去掉代码 – Nate
谢谢Nate - 我马上就会这样做:) – Zephyr
从快速一瞥,不要在插补界限中使用你的数据框调用即改变'“〜我(bdd $ EE1 + bdd $ EE2 ...''到'“〜我(EE1 + EE2 ...' – user20650