我可以为重置索引指定一个名称吗?
答
您可以在返回的DF调用rename
从reset_index
:
In [145]:
# create a df
df = pd.DataFrame(np.random.randn(5,3))
df
Out[145]:
0 1 2
0 -2.845811 -0.182439 -0.526785
1 -0.112547 0.661461 0.558452
2 0.587060 -1.232262 -0.997973
3 -1.009378 -0.062442 0.125875
4 -1.129376 3.282447 -0.403731
设置索引名
In [146]:
df.index = df.index.set_names(['foo'])
df
Out[146]:
0 1 2
foo
0 -2.845811 -0.182439 -0.526785
1 -0.112547 0.661461 0.558452
2 0.587060 -1.232262 -0.997973
3 -1.009378 -0.062442 0.125875
4 -1.129376 3.282447 -0.403731
呼叫reset_index
和链rename
:
In [147]:
df.reset_index().rename(columns={df.index.name:'bar'})
Out[147]:
bar 0 1 2
0 0 -2.845811 -0.182439 -0.526785
1 1 -0.112547 0.661461 0.558452
2 2 0.587060 -1.232262 -0.997973
3 3 -1.009378 -0.062442 0.125875
4 4 -1.129376 3.282447 -0.403731
感谢@ ayhan
或者你可以使用rename_axis
到索引之前reset_index
重命名:
In [149]:
df.rename_axis('bar').reset_index()
Out[149]:
bar 0 1 2
0 0 -2.845811 -0.182439 -0.526785
1 1 -0.112547 0.661461 0.558452
2 2 0.587060 -1.232262 -0.997973
3 3 -1.009378 -0.062442 0.125875
4 4 -1.129376 3.282447 -0.403731
或只是简单地覆盖索引名直接第一:
df.index.name = 'bar'
,然后调用reset_index
你会必须做'df.reset_index()。rename(columns = {df.index.name:'foo'})' – EdChum