如何在离子2中添加两个阵列数据

Question

我是Ionic 2的新手。我想根据它们的位置添加数组元素。例如： ：我有2个数组。

1. 标贴：[而百合，非洲菊，非洲菊，而百合，玫瑰，玫瑰]

2. 数据：[10，20，10，30，20,10]

现在我想从标签[]删除冗余并希望从数据添加它们的值[]

我最后的阵列应该是

个

标签：[而百合，非洲菊，玫瑰]

数据：[40,30,30]

我已经从Json的提取的数据这种类型的：

var qp = [] 
     for (var i of res.data) { 
      qp.push(i.quantity_produced); 
     console.log(res.data); 
     console.log(qp); 

     var name = [] 
      for (var i of res.data) { 
      name.push(i.product); 
       var s= [new Set(name)]; 
     console.log(res.data); 
     console.log(name); 

Answer 1

试试这个：

let labels = ['Lillium', 'Gerbera', 'Gerbera', 'Lillium', 'Rose', 'Rose']; 
 
let Data = [10, 20, 10, 30, 20, 10]; 
 

 
//for each unique label.... 
 
let result = [...new Set(labels)] 
 

 
//... get each occurence index ... 
 
.map(value => labels.reduce((curr, next, index) => { 
 
    if (next == value) 
 
    curr.push(index); 
 
    return curr; 
 
}, [])) 
 

 
//... and reducing each array of indexes using the Data array gives you the sums 
 
.map(labelIndexes => labelIndexes.reduce((curr, next) => { 
 
    return curr + Data[next]; 
 
}, 0)); 
 

 
console.log(result);

基于您的评论看来，事情可以做了很多更容易

let data = [{product: 'Lillium',quantity_produced: 10}, {product: 'Gerbera',quantity_produced: 20},{product: 'Gerbera',quantity_produced: 10}, {product: 'Lillium',quantity_produced: 30}, {product: 'Rose',quantity_produced: 20}, {product: 'Rose',quantity_produced: 10}]; 
 

 
let result = data.reduce((curr, next) => { 
 
    curr[next.product] = (curr[next.product] || 0) + next.quantity_produced; 
 
    return curr; 
 
}, {}); 
 

 
console.log(result);