Java - 无限循环Singleton类的方法调用
问题描述:
我有一个关于单例类的问题。当我调用方法next()时,我期望mProcessIndex会增加,但实际上,它不会导致*错误。所以,问题是修改mProcessIndex值的正确方法是什么?Java - 无限循环Singleton类的方法调用
代码如下:
public class HomePopupDisplayManager {
private static HomePopupDisplayManager sInstance;
private List<WeakReference<HomePopupMessage>> mMessages;
private int mProcessIndex;
private HomePopupDisplayManager() {
mMessages = new ArrayList<>();
mProcessIndex = 0;
}
public static synchronized HomePopupDisplayManager getInstance() {
if (sInstance == null) {
sInstance = new HomePopupDisplayManager();
}
return sInstance;
}
public void register(@NonNull HomePopupMessage message, @IntRange(from = 0) int order) {
mMessages.add(order, new WeakReference<>(message));
}
public void next() {
if (mProcessIndex >= 0 && mProcessIndex < mMessages.size()) {
HomePopupMessage message = mMessages.get(mProcessIndex).get();
if (message != null) {
next();
mProcessIndex++;
}
}
}
}
答
的问题是:
next();
mProcessIndex++;
应该是:
mProcessIndex++;
next();
答
你的下一个()函数进入无限递归循环的在递增mProcessIndex之前调用相同的。因此mProcessIndex i从未增加过。调用mProcessIndex ++在下一个()之前;
愚蠢的错误..谢谢 –