如何获得两个字符串之间最重复的子字符串？

Question

例如，我有两个字符串：

$str1 = "one two three"; 

$str2 = "one two two three three three"; 

我怎样才能得到作为最终结果在上述情况下？

Answer 1

使用这段代码：

$arr = array_count_values(explode(" ", $yourstr)); 
asort($arr); 

reset($array); 

//get first val 
echo current($array), PHP_EOL ; 

//get first key 
echo key($array), PHP_EOL ; 

更多信息，请参阅：php manual

Answer 2

您可以使用爆炸，并把该值阵列。然后根据您创建的数组的索引获取您想要的值。

Answer 3

试试这个

$str1 = "one two three"; 

$str2 = "one two two three three three"; 

$array1=explode(" ",$str1); 
$array2=explode(" ",$str2); 
$result=array_merge($array1,$array2); 
$count=array_count_values($result); 
arsort($count); 
echo key($count); 

Answer 4

$words = "one two two three three three"; 
print_r(array_count_values(str_word_count($words, 1))); 

输出

Array 
(
    [one] => 1 
    [two] => 2 
    [three] => 3 
) 

为str_word_count和array_count_values