如何获得特定字符后的所有字符字符串SQL
我有一个包含有以下形式的字符串行一列:如何获得特定字符后的所有字符字符串SQL
#S6TF3.01,#S6TF3.09,#S6TF3.10,#S6TF3.13
我希望能够得到所有行的结果如下:
01,09,10,13
我使用T-SQL,并尝试以下操作:
SUBSTRING(E.REJECT_WF_NOS, CHARINDEX('.', E.REJECT_WF_NOS) + 1, LEN(E.REJECT_WF_NOS))
我可能会分裂因为结构不是固定的你似乎只想要小数点后的值。这会将逗号分隔,然后在小数点后取所有内容,然后将其重新连接到一个字符串中。
declare @var varchar(64) = 'S6TF3.01,#S6TF3.09,#S6TF3.10,#S6TF3.13'
SELECT
STUFF((
SELECT ',' + substring(item,charindex('.',Item) + 1,32)
FROM dbo.DelimitedSplit8K(@var,',')
FOR XML PATH(''), TYPE).value('.', 'NVARCHAR(MAX)'), 1, 1, '')
Here Is the Function from Jeff Moden
CREATE FUNCTION [dbo].[DelimitedSplit8K] (@pString VARCHAR(8000), @pDelimiter CHAR(1))
--WARNING!!! DO NOT USE MAX DATA-TYPES HERE! IT WILL KILL PERFORMANCE!
RETURNS TABLE WITH SCHEMABINDING AS
RETURN
/* "Inline" CTE Driven "Tally Table" produces values from 1 up to 10,000...
enough to cover VARCHAR(8000)*/
WITH E1(N) AS (
SELECT 1 UNION ALL SELECT 1 UNION ALL SELECT 1 UNION ALL
SELECT 1 UNION ALL SELECT 1 UNION ALL SELECT 1 UNION ALL
SELECT 1 UNION ALL SELECT 1 UNION ALL SELECT 1 UNION ALL SELECT 1
), --10E+1 or 10 rows
E2(N) AS (SELECT 1 FROM E1 a, E1 b), --10E+2 or 100 rows
E4(N) AS (SELECT 1 FROM E2 a, E2 b), --10E+4 or 10,000 rows max
cteTally(N) AS (--==== This provides the "base" CTE and limits the number of rows right up front
-- for both a performance gain and prevention of accidental "overruns"
SELECT TOP (ISNULL(DATALENGTH(@pString),0)) ROW_NUMBER() OVER (ORDER BY (SELECT NULL)) FROM E4
),
cteStart(N1) AS (--==== This returns N+1 (starting position of each "element" just once for each delimiter)
SELECT 1 UNION ALL
SELECT t.N+1 FROM cteTally t WHERE SUBSTRING(@pString,t.N,1) = @pDelimiter
),
cteLen(N1,L1) AS(--==== Return start and length (for use in substring)
SELECT s.N1,
ISNULL(NULLIF(CHARINDEX(@pDelimiter,@pString,s.N1),0)-s.N1,8000)
FROM cteStart s
)
--===== Do the actual split. The ISNULL/NULLIF combo handles the length for the final element when no delimiter is found.
SELECT ItemNumber = ROW_NUMBER() OVER(ORDER BY l.N1),
Item = SUBSTRING(@pString, l.N1, l.L1)
FROM cteLen l
;
GO
干得好。但是,我会将nvarchar(max)更改为varchar(64)。该值>数据类型定义了输出字符串的数据类型,这意味着您将在varchar(64)执行时返回nvarchar(max)。并且转换将隐含。 –
下面是一个简单的版本2016,如果你想它rowbased
select reverse(substring(reverse(value),1,2)),* from
string_split('#S6TF3.01,#S6TF3.09,#S6TF3.10,#S6TF3.13',',')
结果多行 - 2016年
如果你想在一排而已,这可能是2016年的方式
DECLARE @MyTable TABLE
(
ID int ,
Strings varchar(10)
)
INSERT INTO @MyTable (ID,Strings)
select 1,reverse(substring(reverse(value),1,2)) as SplittedValues
from string_split('#S6TF3.01,#S6TF3.09,#S6TF3.10,#S6TF3.13',',')
---Select * from @MyTable
SELECT ID, NewVales = STUFF((SELECT N', ' + Strings
FROM @MyTable AS p2
WHERE p2.ID = p.ID
ORDER BY Strings
FOR XML PATH(N'')), 1, 2, N'')
FROM @MyTable AS p
GROUP BY ID
ORDER BY ID;
结果1排 - 2016
对于t他甚至不需要分配器;你可以使用parsename来“分割”这些值。
declare @string varchar(100) = '#S6TF3.01,#S6TF3.09,#S6TF3.10,#S6TF3.13';
select newString = stuff
((select ','+substring(item, 1, charindex(',', item)-1)
from (values (4),(3),(2),(1)) t(n)
cross apply (values (substring(@string, charindex('.',@string)+1, 8000)+',')) s(string)
cross apply (values (parsename(string,n))) split(item)
for xml path('')), 1,1,'');
这将是比delimitedsplit8k更快,不需要的SQL Server 2016在SQL服务器2017年,你可以进一步简化如下:
select string_agg(substring(item, 1, charindex(',', item)-1),',')
from (values (4),(3),(2),(1)) t(n)
cross apply (values (substring(@string, charindex('.',@string)+1, 8000)+',')) s(string)
cross apply (values (parsename(string,n))) split(item)
只是一个注释,该函数不需要SQL Server 2016年我喜欢parsename虽然如果有不超过4个值。 – scsimon
如果你有这样的行数据由行类似如下表结构:
ID DATA
1 #S6TF3.01
2 #S6TF3.09
3 #S6TF3.10
4 #S6TF3.13
如果你始终像数据如上然后只写子功能如下:
SELECT SUBSTRING(DATA, 8, 2) DATA from #TEMP
结果:
ID DATA Result
1 #S6TF3.01 01
2 #S6TF3.09 09
3 #S6TF3.10 10
4 #S6TF3.13 13
如果是这样构成的数据库也不是那么好... – decadenza
如果背后总有小数2号,我会用string_split在2016年,以用逗号分割,然后颠倒你的行和子串2,然后将其逆转回去:) – plaidDK