jQuery的JSON格式错误
问题描述:
{"simpleSearchResult" :
{
"facultydetail":
[
{"comboValue":"FACULTY"},
{"facultyDetail":
[
"Android",
"Android profile",
"balaguru",
"Ulsoor",
"[email protected]",
"Bangalore",
"Karnataka",
"India",
"83",
"3 years of teaching experiance",
"INR",
"10000.0",
"40",
"20000.0"
]
},
{"NunberOfPages":"1"},
{"CurrentPage":"1"},
{"SkillIds":"an"},
{"cityId":"ba"},
{"DisplayCboValue":"STUDENT"},
{"Limit":"0"},
{"PageComboVal":"10"},
{"discipline":"Languages"}
]
}
}
这是从我的Action类JSON字符串我是回这jQuery的Ajax调用但总是会出错块,gving解析错误的任何一个,请帮我解决这个问题jQuery的JSON格式错误
JSON是有效的 - 你的代码的其余部分是错误的? – diagonalbatman 2011-01-07 15:40:09
重新格式化您的帖子,摆脱大写锁定,让我们看看你在说什么。同时添加错误输出。 – sjngm 2011-01-07 15:41:14