XML JavaScript绘制网络图
问题描述:
我正在尝试使用XML和JavaScript创建圆环图。XML JavaScript绘制网络图
我试过用这个d3.v3.min.js库。我试着用我的js编码来检查和循环XML中的数据并存储在数组中。然后我试着运行编码来绘制网络图。
$(document).ready(function(){
$.ajax({
type: "GET",
url: "data.xml",
dataType: "xml",
success: function(xml){
var links = [];
$(xml).find('name').each(function(){
var name = $(this);
var source = $name.attr("source");
var target = $name.attr("target");
links.push([source, target]);
});
var nodes ={};
// Compute the distinct nodes from the links.
links.forEach(function(link) {
link.source = nodes[link.source] || (nodes[link.source] = {name: link.source});
link.target = nodes[link.target] || (nodes[link.target] = {name: link.target});
});
visualizeIt();
},
error: function() {
alert("An error occurred while processing XML file.");
}
});
});
对于绘制网络图的一部分,
function visualizeIt() {
var width = 960,
height = 500;
var force = d3.layout.force()
.nodes(d3.values(nodes))
.links(links)
.size([width, height])
.linkDistance(60)
.charge(-300)
.on("tick", tick)
.start();
var svg = d3.select("body").append("svg")
.attr("width", width)
.attr("height", height);
var link = svg.selectAll(".link")
.data(force.links())
.enter().append("line")
.attr("class", "link");
var node = svg.selectAll(".node")
.data(force.nodes())
.enter().append("g")
.attr("class", "node")
.on("mouseover", mouseover)
.on("mouseout", mouseout)
.call(force.drag);
node.append("circle")
.attr("r", 8);
node.append("text")
.attr("x", 12)
.attr("dy", ".35em")
.text(function(d) { return d.name; });
function tick() {
link
.attr("x1", function(d) { return d.source.x; })
.attr("y1", function(d) { return d.source.y; })
.attr("x2", function(d) { return d.target.x; })
.attr("y2", function(d) { return d.target.y; });
node
.attr("transform", function(d) { return "translate(" + d.x + "," + d.y + ")"; });
}
function mouseover() {
d3.select(this).select("circle").transition()
.duration(750)
.attr("r", 16);
}
function mouseout() {
d3.select(this).select("circle").transition()
.duration(750)
.attr("r", 8);}
}
这是我data.xml中
<?xml version="1.0" encoding="utf-8" ?>
<note>
<name source = "Math" target = "Science" />
<name source = "Bio" target = "Geo" />
<name source = "Science" target = "Astro" />
<name source = "Science" target = "Histo" />
</note>
我认为,存在的第一部分缺失的部分或概念的误解编码。任何人都请纠正我。
答
XML
<?xml version="1.0" encoding="utf-8" ?>
<course>
<source>Math</source>
</course>
<subcourse>
<target>Science</target>
</subcourse>
</course>
<course>
<source>Bio</source>
</course>
<subcourse>
<target>Geo</target>
</subcourse>
</course>
JavaScript编码
$(document).ready(function(){
$.ajax({
type: "GET",
url: "data.xml",
dataType: "xml",
success: function(xml){
var links = [];
var nodes = {};
$(xml).find('course').each(function(){
var getSource = $(this).find('source').text();
$(this).find('target').each(function(){
var getTarget = $(this).text();
links.push({source:getSource, target:getTarget});
});
});
// Compute the distinct nodes from the links.
links.forEach(function(link) {
link.source = nodes[link.source] || (nodes[link.source] = {name: link.source});
link.target = nodes[link.target] || (nodes[link.target] = {name: link.target});
});
var width = 960,
height = 500;
var force = d3.layout.force()
.nodes(d3.values(nodes))
.links(links)
.size([width, height])
.linkDistance(60)
.charge(-300)
.on("tick", tick)
.start();
var svg = d3.select("body").append("svg")
.attr("width", width)
.attr("height", height);
var link = svg.selectAll(".link")
.data(force.links())
.enter().append("line")
.attr("class", "link");
var node = svg.selectAll(".node")
.data(force.nodes())
.enter().append("g")
.attr("class", "node")
.on("mouseover", mouseover)
.on("mouseout", mouseout)
.call(force.drag);
node.append("circle")
.attr("r", 8);
node.append("text")
.attr("x", 12)
.attr("dy", ".35em")
.text(function(d) { return d.name; });
function tick() {
link
.attr("x1", function(d) { return d.source.x; })
.attr("y1", function(d) { return d.source.y; })
.attr("x2", function(d) { return d.target.x; })
.attr("y2", function(d) { return d.target.y; });
node
.attr("transform", function(d) { return "translate(" + d.x + "," + d.y + ")"; });
}
function mouseover() {
d3.select(this).select("circle").transition()
.duration(750)
.attr("r", 16);
}
function mouseout() {
d3.select(this).select("circle").transition()
.duration(750)
.attr("r", 8);
};
},
});
});
这让我坚持几天。最后在这里发布我的答案。
你应该一步一步来做 – Mahi
我一步一步做了......只是无法弄清楚什么是错误..我不知道哪个部分是错误的..在第1部分或data.xml中 – kenreal
如果你做了一步你可以看到哪一部分是错的。 – Mahi