如何将项目添加到我的关联数组中?
我定义我的数组如何将项目添加到我的关联数组中?
$data = array();
增加1项:
$data['response'] = true;
现在我想在添加多个项目曾经这样:
$data["picUpload" => $pPicUpload, "Album1" => $Album1, "Album2" => $Album2];
但我得到这个错误:
parse error, expecting `']''
我在做什么错?
你可以把它写在多条线路,如:
$data['new0'] = 'value0';
$data['new1'] = 'value1';
或使用array_merge(将覆盖碰撞键):
$data = array_merge($data, array('new0' => 'value0', 'new1' => 'value1'));
您需要通过一个加一个,或者使用array_merge
方法。
$data["picUpload"] =$pPicUpload;
$data["Album1"] = $Album1;
$data["Album2"] = $Album2;
您使用的语法不正确。您需要使用array_merge功能
$data = array_merge($data, array(
"picUpload" => $pPicUpload,
"Album1" => $Album1,
"Album2" => $Album2
));
$data = array_merge($data, Array("picUpload" => $pPicUpload, "Album1" => $Album1, "Album2" => $Album2));
为什么不干脆:
$data["picUpload"] = $pPicUpload;
$data["Album1"] = $Album1;
$data["Album2"] = $Album2;
,因为我知道这是可以做到这一点,因为我描述,我想了解为什么它不适合我 – 2012-08-02 07:19:14
学习新东西总是很好:) – 2012-08-02 07:26:54
试试这个:
$data = array("picUpload" => $pPicUpload, "Album1" => $Album1, "Album2" => $Album2);
试试这个,
$data = array("picUpload" => $pPicUpload, "Album1" => $Album1, "Album2" => $Album2);
这不是什么保罗问:) – 2012-08-02 07:13:33
$ data = array(“picUpload”=> $ pPicUpload,“Album1”=> $ Album1,“Album2”=> $ Album2); – Debugger 2012-08-02 07:12:19