Groovy的XML解析然后重建
问题描述:
比从daviderossi.blogspot.com我已经得到了一些帮助更多的得到一些代码的工作,以取代另一个Groovy的XML解析然后重建
def fm_xml = '''<?xml version="1.0" encoding="UTF-8"?>
<MAlong>
<Enquiry.ID>SC11147</Enquiry.ID>
<student.name_middle></student.name_middle>
<student.name_known></student.name_known>
<student.name_previous></student.name_previous>
<student.name_cert>John REnfrew</student.name_cert>
<student.detail_gender>M</student.detail_gender>
<student.sign_name>John Renfrew</student.sign_name>
<student.sign_date>05/01/2010</student.sign_date>
</MAlong>'''
xml = new XmlParser().parseText(fm_xml)
ix = xml.children().findIndexOf{it.name() =='student.name_middle'}
nn = new Node(xml, 'student.name_middle', "NEW")
if (ix != -1) {
xml.children()[ix] = nn
nn.parent = xml
}
writer = new StringWriter()
new XmlNodePrinter(new PrintWriter(writer)).print(xml)
result = writer.toString()
XML值这给我下面的输出,但我喜欢它,是用正确形成结束标记,否则XPath查询新数据,然后将失败..
因此,例如
<student.name_known/>
需求,成为
<student.name_known></student.name_known>
任何想法??
<MAlong>
<Enquiry.ID>
SC11147
</Enquiry.ID>
<student.name_middle>
NEW
</student.name_middle>
<student.name_known/>
<student.name_previous/>
<student.name_cert>
John REnfrew
</student.name_cert>
<student.detail_gender>
M
</student.detail_gender>
<student.sign_name>
John Renfrew
</student.sign_name>
<student.sign_date>
05/01/2010
</student.sign_date>
<student.name_middle>
NEW
</student.name_middle>
</MAlong>
答
<student.name_known/>
是完全中规中矩,和XPath查询应该便能很好地工作在这个XML结构。
答
它应该工作通过设置expandEmptyElements选项设置为true
看到http://groovy.codehaus.org/api/groovy/util/XmlNodePrinter.html#setExpandEmptyElements%28boolean%29
认为我有一个复制和粘贴错误,它确实没有工作,但仍有意使其稍微更具可读性 – 2010-07-19 06:41:24
一般来说,您没有这种使用XML解析的控制级别。我没有看到Groovy有任何明显的'漂亮打印'选项,但任何解决方案可能都不值得。 – Dunderklumpen 2010-07-20 03:39:17