无法反序列化的XML字符串
我有以下XML这我想反序列化如下,但我得到的错误:无法反序列化的XML字符串
There was an error reflecting type 'System.Collections.Generic.List`1[MyApp.Models.Field]
下面是我的代码
public class FieldList
{
[XmlArray("fields")]
[XmlArrayItem("field")]
List<Field> Fields { get; set; }
}
public class Field
{
[XmlAttribute("type")]
public string Type { get; set; }
[XmlAttribute("required")]
public bool Required { get; set; }
[XmlAttribute("label")]
public string Label { get; set; }
[XmlAttribute("name")]
public string Name { get; set; }
[XmlElement("option")]
[JsonProperty("values")]
public List<Option> Options { get; set; }
}
public class Option
{
[XmlAttribute("label")]
public string Label { get; set; }
[XmlAttribute("value")]
public string Value { get; set; }
[XmlAttribute("selected")]
public bool Selected { get; set; }
/// <remarks/>
[XmlIgnore()]
public bool SelectedSpecified { get; set; }
[XmlText]
public string Text { get; set; }
}
var xml = @"<?xml version=""1.0"" ?>
<form-template>
<fields>
<field type=""select"" required=""true"" label=""Cars"" name=""cars"" >
<option label=""Toyota"" value=""Toyota"" selected=""true"">Toyota</option>
<option label=""Nisan"" value=""Nisan"" >Nisan</option>
</field>
</fields>
</form-template>";
var serializer = new XmlSerializer(typeof(FieldList), new XmlRootAttribute("form-template"));
var stringReader = new StringReader(xml);
var xmlFields = (FieldList)serializer.Deserialize(stringReader);
我在做什么错误?
* UPDATE *
按照下面的意见改变
public IEnumerable<Option> Options { get; set; }
要
public List<Option> Options { get; set; }
修正错误,但现在没有什么是反序列化 - 变量xmlFields
是空???我需要从特定的节点读取还是不重要?
让我们来看看你的代码。
new XmlRootAttribute("form-template")
映射到<form-template>
节点。
public class Field
映射到<field
节点。
但没有映射到<fields>
节点。
添加下面的类:
public class FieldList
{
[XmlArray("fields")]
[XmlArrayItem("field")]
public List<Field> Fields { get; set; }
}
它应该工作:
var serializer = new XmlSerializer(typeof(FieldList), new XmlRootAttribute("form-template"));
var stringReader = new StringReader(xml);
var xmlFields = (FieldList)serializer.Deserialize(stringReader);
此外,你应该将属性添加到Option
类:
[XmlText]
public string Text { get; set; }
更新。
你可以摆脱FieldList
类。但是,您必须手动跳过部分xml节点。
List<Field> xmlFields;
var serializer = new XmlSerializer(typeof(List<Field>), new XmlRootAttribute("fields"));
// You can read from a stream or from a StringReader instead of a file
using (var xmlReader = XmlReader.Create("test.xml"))
{
// Skip <form-template> node
xmlReader.ReadToFollowing("fields");
xmlFields = (List<Field>)serializer.Deserialize(xmlReader);
}
添加XmlType
属性类:
[XmlType("field")]
public class Field
的XmlSerializer无法序列抽象属性,请更改的IEnumerable列出像下面,
public IEnumerable<Option> Options { get; set; }
到
public List<Option> Options { get; set; }
您根元素不与你有XML的结构匹配。我已经编辑XML像下面,
var xml = "<?xml version=\"1.0\" ?>" +
" " +
" <Fields>" +
" <Field Type=\"select\" Required=\"true\" Label=\"Cars\" Name=\"cars\" >" +
" <option label=\"Toyota\" lalue=\"Toyota\" selected=\"true\">Toyota</option>" +
" <option label=\"Nisan\" value=\"Nisan\" >Nisan</option>" +
" </Field>" +
" </Fields>";
和反序列化的代码作为,
XmlSerializer serializer = new XmlSerializer(typeof(List<Field>), new XmlRootAttribute("Fields"));
var stringReader = new StringReader(xml);
List<Field> xmlFields = (List<Field>)serializer.Deserialize(stringReader);
现在它被反序列化的罚款。请参阅输出,
更改为'列表
“Option”类是否标有'[Serializable]'属性?它有无参数CTOR吗? – Moerwald
@Moerwald - “XmlSerializer”类不使用“Serializable'属性。 –
您需要正确生成类要序列化的XML。将不含双“双引号”的正确XML复制到剪贴板中,转到Visual Studio解决方案中的任何cs文件。点击编辑 - >选择性粘贴 - >将XML粘贴为类。这将正确地生成您的cs文件中的转换类。然后,将这些更改为自动实现的属性,而不是使用私有变量来减少屏幕上的混乱。
与所述一组以下类,反序列化作为
XmlSerializer serializer = new XmlSerializer(typeof(FormTemplate));
var xml = @"<?xml version=""1.0"" ?>
<form-template>
<fields>
<field type=""select"" required=""true"" label=""Cars"" name=""cars"" >
<option label=""Toyota"" value=""Toyota"" selected=""true"">Toyota</option>
<option label=""Nisan"" value=""Nisan"" >Nisan</option>
</field>
</fields>
</form-template>";
var stringReader = new StringReader(xml);
var xmlFields = serializer.Deserialize(stringReader);
自动生成的一组的修改,以改变 属性来自动实现的属性的类。
/// <remarks/>
[System.Xml.Serialization.XmlTypeAttribute(AnonymousType = true)]
[System.Xml.Serialization.XmlRootAttribute("form-template", Namespace = "", IsNullable = false)]
public partial class FormTemplate
{
/// <remarks/>
public Fields fields { get; set; }
}
/// <remarks/>
[System.Xml.Serialization.XmlTypeAttribute(AnonymousType = true)]
public partial class Fields
{
/// <remarks/>
public SingleField field { get; set; }
}
/// <remarks/>
[System.Xml.Serialization.XmlTypeAttribute(AnonymousType = true)]
public partial class SingleField
{
/// <remarks/>
[System.Xml.Serialization.XmlElementAttribute("option")]
public Option[] option { get; set; }
/// <remarks/>
[System.Xml.Serialization.XmlAttributeAttribute()]
public string type { get; set; }
/// <remarks/>
[System.Xml.Serialization.XmlAttributeAttribute()]
public bool required { get; set; }
/// <remarks/>
[System.Xml.Serialization.XmlAttributeAttribute()]
public string label { get; set; }
/// <remarks/>
[System.Xml.Serialization.XmlAttributeAttribute()]
public string name { get; set; }
}
/// <remarks/>
[System.Xml.Serialization.XmlTypeAttribute(AnonymousType = true)]
public partial class Option
{
/// <remarks/>
[System.Xml.Serialization.XmlAttributeAttribute()]
public string label { get; set; }
/// <remarks/>
[System.Xml.Serialization.XmlAttributeAttribute()]
public string value { get; set; }
/// <remarks/>
[System.Xml.Serialization.XmlAttributeAttribute()]
public bool selected { get; set; }
/// <remarks/>
[System.Xml.Serialization.XmlIgnoreAttribute()]
public bool selectedSpecified { get; set; }
/// <remarks/>
[System.Xml.Serialization.XmlTextAttribute()]
public string Value { get; set; }
}
的'InnerException'应该包含一个线索。 –
@ManfredRadlwimmer将IEnumerable
我最好的猜测是,因为以下属性是一个接口 public IEnumerable