注入服务为使用Autofac
问题描述:
TL基类; DR:如何可以巩固通过两个自定义ModelBinder
实现共享成一个单一的基类的逻辑,当两个实现依赖于Autofac注入一个(共同的)的依赖性放进去?注入服务为使用Autofac
在审查一个ASP.NET MVC项目我工作的一些代码,我意识到,我有两个自定义模型粘合剂,基本上他们做同样的事情。它们都从DefaultModelBinder
继承,它们都使用注入到其构造函数中的IEncodingService
对两个单独的视图模型类编码单个属性。
public class ResetQuestionAndAnswerViewModelBinder : DefaultModelBinder {
public ResetQuestionAndAnswerViewModelBinder(IEncodingService encodingService) {
encoder = encodingService;
}
private readonly IEncodingService encoder;
public override object BindModel(ControllerContext controllerContext,
ModelBindingContext bindingContext) {
var model = base.BindModel(controllerContext, bindingContext) as ResetQuestionAndAnswerViewModel;
if (model != null) {
var answer = bindingContext.ValueProvider.GetValue("Answer");
if ((answer != null) && !(answer.AttemptedValue.IsNullOrEmpty())) {
model.Answer = encoder.Encode(answer.AttemptedValue);
}
}
return model;
}
}
public class ConfirmIdentityViewModelBinder : DefaultModelBinder {
public ConfirmIdentityViewModelBinder(IEncodingService encodingService) {
encoder = encodingService;
}
private readonly IEncodingService encoder;
public override object BindModel(ControllerContext controllerContext,
ModelBindingContext bindingContext) {
var model = base.BindModel(controllerContext, bindingContext) as ConfirmIdentityViewModel;
if (model != null) {
var secretKey = bindingContext.ValueProvider.GetValue("SecretKey");
if ((secretKey != null) && !(secretKey.AttemptedValue.IsNullOrEmpty())) {
model.SecretKeyHash = encoder.Encode(secretKey.AttemptedValue);
}
}
return model;
}
}
我写了一个通用的基类,这两个类要继承:
public class EncodedPropertyModelBinder<TViewModel> : DefaultModelBinder
where TViewModel : class {
public EncodedPropertyModelBinder(IEncodingService encodingService,
string propertyName) {
encoder = encodingService;
property = propertyName;
}
private readonly IEncodingService encoder;
private readonly string property;
public override object BindModel(ControllerContext controllerContext,
ModelBindingContext bindingContext) {
var model = base.BindModel(controllerContext, bindingContext) as TViewModel;
if (model != null) {
var value = bindingContext.ValueProvider.GetValue(property);
if ((value != null) && !(value.AttemptedValue.IsNullOrEmpty())) {
var encodedValue = encoder.Encode(value.AttemptedValue);
var propertyInfo = model.GetType().GetProperty(property);
propertyInfo.SetValue(model, encodedValue, null);
}
}
return model;
}
}
使用Autofac,我将如何注入IEncodingService
到基类的构造函数,同时迫使派生类提供要编码的属性的名称?
答
我实际上会略有不同,通过favoring composition over inheritance。这意味着我将封装属性操作的细节,并将不同的实现传递给单个模型绑定器。
首先,定义其表示结合单个属性的接口:
public interface IPropertyBinder
{
void SetPropertyValue(object model, ModelBindingContext context);
}
然后,最初使用的参数从EncodedPropertyModelBinder
实现:
public sealed class PropertyBinder : IPropertyBinder
{
private readonly IEncodingService _encodingService;
private readonly string _propertyName;
public PropertyBinder(IEncodingService encodingService, string propertyName)
{
_encodingService = encodingService;
_propertyName = propertyName;
}
public void SetPropertyValue(object model, ModelBindingContext bindingContext)
{
var value = bindingContext.ValueProvider.GetValue(_propertyName);
if(value != null && !value.AttemptedValue.IsNullOrEmpty())
{
var encodedValue = _encodingService.Encode(value.AttemptedValue);
var property = model.GetType().GetProperty(_propertyName);
property.SetValue(model, encodedValue, null);
}
}
}
接着,实施EncodedPropertyModelBinder
使用新的接口:
public class EncodedPropertyModelBinder : DefaultModelBinder
{
private readonly IPropertyBinder _propertyBinder;
public EncodedPropertyModelBinder(IPropertyBinder propertyBinder)
{
_propertyBinder = propertyBinder;
}
public override object BindModel(ControllerContext controllerContext, ModelBindingContext bindingContext)
{
var model = base.BindModel(controllerContext, bindingContext);
if(model != null)
{
_propertyBinder.SetPropertyValue(model, bindingContext);
}
return model;
}
}
最后,使用Autofac命名实例注册两个版本的视图模型,传入PropertyBinder
的不同配置:
builder.
Register(c => new EncodedPropertyModelBinder(new PropertyBinder(c.Resolve<IEncodingService>(), "Answer")))
.Named<EncodedPropertyModelBinder>("AnswerBinder");
builder.
Register(c => new EncodedPropertyModelBinder(new PropertyBinder(c.Resolve<IEncodingService>(), "SecretKey")))
.Named<EncodedPropertyModelBinder>("SecretKeyBinder");