解析XML存储到NSArray中

Question

我试图解析一个XML并将XML的一个元素的URL存储到一个NSArray中。这是我到目前为止的代码：

NSURL *url = [NSURL URLWithString:@"http://www.316apps.com/LakesideDocs/podcasttrial.xml"]; 

    NSData *xmlData = [[NSMutableData alloc] initWithContentsOfURL:url]; 
    NSError *error; 
    GDataXMLDocument *doc = [[GDataXMLDocument alloc] initWithData:xmlData 
                  options:0 error:&error]; 

    NSArray *channels = [doc.rootElement elementsForName:@"channel"]; 
    for (GDataXMLElement *channel in channels) {    


     NSArray *items = [channel elementsForName:@"item"]; 
     for (GDataXMLElement *item in items) { 

      NSString *articlePoint = [item valueForChild:@"link"]; 
      NSArray *linkarray = [[NSArray alloc] initWithObjects:articlePoint, nil]; 

      NSLog(@"%@", linkarray); 

     } 

    } 

有关的NSLog我希望：

TabBarSample[40191:fb03] (
    (
    "http://domain.com/image1.jpg" 
), 
(
"http://domain.com/image2.jpg" 
) 
) 

，但我得到：

TabBarSample[40191:fb03] (
"http://domain.com/image1.jpg" 
) 
TabBarSample[40191:fb03] (
"http://domain.com/image2.jpg" 
) 

我在做什么错？

Answer 1

与每一个循环中，您创建一个新的数组：

NSArray *linkarray = [[NSArray alloc] initWithObjects:articlePoint, nil]; 

，而不是你想要的LLOP之外的NSMutableArray中，每个循环过程中添加的对象

NSMutableArray *linkarray = [NSMutableArray array]; 
    NSArray *items = [channel elementsForName:@"item"]; 
    for (GDataXMLElement *item in items) { 

     NSString *articlePoint = [item valueForChild:@"link"]; 
     [linkarray addObject:articlePoint]; 

     NSLog(@"%@", linkarray); 

    } 

如果增加阵列是混淆了你，你应该把NSLog后的for循环：

NSMutableArray *linkarray = [NSMutableArray array]; 
    NSArray *items = [channel elementsForName:@"item"]; 
    for (GDataXMLElement *item in items) { 

     NSString *articlePoint = [item valueForChild:@"link"]; 
     [linkarray addObject:articlePoint]; 
    } 

    NSLog(@"%@", linkarray); 
    NSLog(@"count: %d", [linkarray count]);