将Java对象转换为XML并使用DOM/SAX解析它
问题描述:
我需要将Java对象转换为XML对象并将其从服务器发送到客户端浏览器。将Java对象转换为XML并使用DOM/SAX解析它
而在客户端浏览器中,我需要使用DOM/SAX或任何适合并在UI中显示它来解析获得的XML对象。
哪一个适合上述?他们中的任何一个能帮我解决这个问题吗?
答
您可以使用JAXB API解决您的问题。 JAXB(用于XML绑定的Java架构)使用注释将Java对象转换为XML内容或从XML内容转换。 JAXB解决了以下难题:
编组 - 将Java对象转换为XML内容。
Unmarshalling - 将XML内容转换为Java对象。
你可以找到JAXB的简单例子:here。
答
下面是一个简单的Java类使用JAXB Java对象转换为XML内容
import java.io.StringReader;
import java.io.StringWriter;
import javax.xml.bind.JAXBContext;
import javax.xml.bind.Marshaller;
import javax.xml.bind.Unmarshaller;
import javax.xml.bind.annotation.XmlRootElement;
class JavaToXMLContent {
public static void main(String[] args) throws Throwable {
// =============================================================================================================
// Setup JAXB
// =============================================================================================================
// Create a JAXB context passing in the class of the object we want to marshal/unmarshal
final JAXBContext context = JAXBContext.newInstance(JavaObject.class);
// =============================================================================================================
// Marshalling OBJECT to XML
// =============================================================================================================
// Create the marshaller, this is the nifty little thing that will actually transform the object into XML
final Marshaller marshaller = context.createMarshaller();
// Create a stringWriter to hold the XML
final StringWriter stringWriter = new StringWriter();
// Create the sample object we wish to transform into XML
final JavaObject javaObject = new JavaObject();
javaObject.setName("Json");
javaObject.setRole("Moderator");
javaObject.setAge(28);
// Marshal the javaObject and write the XML to the stringWriter
marshaller.marshal(javaObject, stringWriter);
// Print out the contents of the stringWriter
System.out.println(stringWriter.toString());
// =============================================================================================================
// Unmarshalling XML to OBJECT
// =============================================================================================================
// Create the unmarshaller, this is the nifty little thing that will actually transform the XML back into an object
final Unmarshaller unmarshaller = context.createUnmarshaller();
// Unmarshal the XML in the stringWriter back into an object
final JavaObject javaObject2 = (JavaObject) unmarshaller.unmarshal(new StringReader(stringWriter.toString()));
// Print out the contents of the JavaObject we just unmarshalled from the XML
System.out.println(javaObject2.toString());
}
/**
* JavaObject is the sample object we've created to use for marshalling to and from XML.
* Make sure you have the @XmlRootElement annotation at the top there as well or JAXB
* might moan.
*/
@XmlRootElement
private static class JavaObject {
private String name;
private String role;
private int age;
public JavaObject() {
}
public String getName() {
return name;
}
public void setName(String name) {
this.name = name;
}
public String getRole() {
return role;
}
public void setRole(String role) {
this.role = role;
}
public int getAge() {
return age;
}
public void setAge(int age) {
this.age = age;
}
@Override
public String toString() {
return "Name [" + this.name + "], Role [" + this.role + "], Age [" + this.age + "]";
}
}
}
希望这会帮助你。
谢谢。它会将Java转换为XML文件还是XML对象?因为我需要将它转换为XML对象,因为我需要将它传递给客户端,在客户端我需要解析XML内容并在UI中显示它 – Viswa
这将是XML内容。它的基础是要么将XML内容放入XML文件中,要么将其作为XML字符串传递给客户端。 –
是否有可能将静态Java类转换为xmlstring? – Viswa