NSRegularExpression在两个XML标记之间提取文本
问题描述:
如何使用NSRegularExpression提取“badgeCount”标记之间的值“6”。以下是服务器的响应:NSRegularExpression在两个XML标记之间提取文本
<?xml version="1.0" encoding="UTF-8" standalone="yes"?><badgeCount>6</badgeCount><rank>2</rank><screenName>myName</screenName>
以下是我尝试过的代码,但未取得成功。实际上,它在去其他部分并打印“正则表达式的值是无”:
NSString *responseString = [[NSString alloc] initWithBytes:[responseDataForCrntUser bytes] length:responseDataForCrntUser.length encoding:NSUTF8StringEncoding];
NSError *error;
NSRegularExpression *regex = [NSRegularExpression regularExpressionWithPattern:@"(?<=badgeCount>)(?:[^])*?(?=</badgeCount)" options:0 error:&error];
if (regex != nil) {
NSTextCheckingResult *firstMatch = [regex firstMatchInString:responseString options:0 range:NSMakeRange(0, [responseString length])];
NSLog(@"NOT NIL");
if (firstMatch) {
NSRange accessTokenRange = [firstMatch rangeAtIndex:1];
NSString *value = [urlString substringWithRange:accessTokenRange];
NSLog(@"Value: %@", value);
}
}
else
NSLog(@"Value of regex is nil");
如果你能提供将不胜感激示例代码。
注意:我不想使用NSXMLParser。
答
实施例:
NSString *xml = @"<?xml version=\"1.0\" encoding=\"UTF-8\" standalone=\"yes\"?><badgeCount>6</badgeCount><rank>2</rank><screenName>myName</screenName>";
NSString *pattern = @"<badgeCount>(\\d+)</badgeCount>";
NSRegularExpression *regex = [NSRegularExpression
regularExpressionWithPattern:pattern
options:NSRegularExpressionCaseInsensitive
error:nil];
NSTextCheckingResult *textCheckingResult = [regex firstMatchInString:xml options:0 range:NSMakeRange(0, xml.length)];
NSRange matchRange = [textCheckingResult rangeAtIndex:1];
NSString *match = [xml substringWithRange:matchRange];
NSLog(@"Found string '%@'", match);
的NSLog输出:
Found string '6'
答
要做到这一点在迅速3.0
func getMatchingValueFrom(strXML:String, tag:String) -> String {
let pattern : String = "<"+tag+">(\\d+)</"+tag+">"
let regexOptions = NSRegularExpression.Options.caseInsensitive
do {
let regex = try NSRegularExpression(pattern: pattern, options: regexOptions)
let textCheckingResult : NSTextCheckingResult = regex.firstMatch(in: strXML, options: NSRegularExpression.MatchingOptions(rawValue: UInt(0)), range: NSMakeRange(0, strXML.characters.count))!
let matchRange : NSRange = textCheckingResult.rangeAt(1)
let match : String = (strXML as NSString).substring(with: matchRange)
return match
} catch {
print(pattern + "<-- not found in string -->" + strXML)
return ""
}
}
PS:这是相应于obj-的@ zaph的溶液迅速溶液c
为什么你不想要你选择一个XML解析器来解析XML? – Mat
到目前为止您尝试过什么? – Mat
不需要NSXMLParser来提取几个值...我使用http://使用正则表达式“(?)(?:[^])??(?= badgeCount)” gskinner.com/RegExr/在线工具,但无法在NSRegular Expression中使用相同的表达式... – Prazi